Question

A test was given to a group of students. The grades and gender are summarized below A B C Total Male 6 17 16 39 Female 19 9 15 43 Total 25 26 31 82 If one student is chosen at random from those who took the test, Find the probability that the student got a 'C' GIVEN they are male

Answer 1

We'll use this table (below) to answer the questions

	A	B	C	Total
Male	6	17	16	39
Female	19	9	15	43
Total	25	26	31	82

Question: If one student is chosen at random, Find the probability that the student was male AND got a "C":

There are 82 students total (see bottom right corner).

There are 16 males who got a C. Look at the first row (male row) and the second columb (Ccolumn).

P(male AND got a C) = (number of males who got a C)/(number total) = (16)/(82) = 0.1951

Note: Don't forget to fully reduce any fractions as much as possible.

Answer in decimal form: 0.1951 (approximate)
Answer in percent form: 19.51% (approximate)

Question: If one student is chosen at random, Find the probability that the student was male:
There are 82 students total (see bottom right corner). Out of these 82students, there are 39 total males (see row 1, last column)

The probability of picking a male is therefore,

P(Male) = (number of males)/(number total) = 39/82

The answer for this sub-question is 39/82. This is write in fraction form. If she or he wants you to write it in decimal form, then 39/82 = 0.4756 approximately which converts to 47.56%

Answer in fraction form: 39/82
Answer in decimal form: 0.4756 (round this however you are instructed to)
Answer in percent form: 47.56% (round this however you are instructed to)