Question
In: Math
An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ...
An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ = 45 and σ = 4.5.
(a) What is the probability that yield strength is at most 40? Greater than 63? (Round your answers to four decimal places.)
| at most 40 | ||
| greater than 63 |
(b) What yield strength value separates the strongest 75% from the
others? (Round your answer to three decimal places.)
ksi
Solutions
Expert Solution
µ = 45
sd = 4.5
a) 
= P(Z < 1.11)
= 0.8665
b) 
= P(Z > 4)
= 1 - P(Z < 4)
= 1 - 1
= 0
b) 
or, x = 45 - 0.67 * 4.5
or, x = 41.985 (ans)
milcah answered 6 months agoRelated Solutions
An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ...
An article suggested that yield strength (ksi) for A36 grade
steel is normally distributed with μ = 44 and σ =
4.5.
(a) What is the probability that yield strength is at most 38?
Greater than 60? (Round your answers to four decimal places.)
at most 38
greater than 60
What yield strength value separates the strongest 75% from the
others? (Round your answer to three decimal places.)
__________ ksi
An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ...
An article suggested that yield strength (ksi) for A36 grade
steel is normally distributed with μ = 44 and σ =
5.0.
(a) What is the probability that yield strength is at most 40?
Greater than 64? (Round your answers to four decimal places.)
at most 40
greater than 64
(b) What yield strength value separates the strongest 75% from the
others? (Round your answer to three decimal places.)
____________ ksi
Assume that yield strength (ksi) for a steel is normally distributed with (sigma)^2 = 4. Assume...
Assume that yield strength (ksi) for a steel is normally
distributed with (sigma)^2 = 4. Assume (mu)= 12 What is the yield
strength value separates the strongest 6-% from the others? What is
the probability that sample mean of yield strength is less than
12.5 for sample size 50? Assume the 99% confidence interval for
(mu) is (7.7,9.2), what would be a 90% confidence interval
calculated from the same sample size and sample mean? Assume we
have a sample set...
An ASTM A36 steel having a yield strength of 235 MPa, a tensile strength of 640...
An ASTM A36 steel having a yield strength of 235 MPa, a tensile
strength of 640 MPa, and an endurance limit of 210 MPa is subjected
to a cyclic loading. Using the Goodman diagram, predict whether the
material has an infinite fatigue life, or whether it will fail by
yielding or fatigue, when the cyclic stress is between:
(i) 0 and 250 MPa.
(ii) 95 ± 220 MPa
Using the column interaction diagrams in Appendix A (Concrete strength = 5 ksi, steel reinforcement yield...
Using the column interaction diagrams in Appendix A (Concrete
strength = 5 ksi, steel reinforcement yield strength= 60 ksi,) with
longitudinal reinforcement ration of approximately 2%, design
square columns with equal reinforcement on all sides to carry each
of the following loads and select the longitudinal and transverse
reinforcement: 1. Pu = 2000 kips and Mu = 160 ft.kips 2. Pu = 1000
kips and Mu = 220 ft.kips 3. Pu = 500 kips and Mu = 160 ft.kips
A. A company produces steel rods. The lengths of the steel rods are normally distributed with...
A. A company produces steel rods. The lengths of the steel rods
are normally distributed with a mean of 162.4-cm and a standard
deviation of 0.6-cm. For shipment, 16 steel rods are bundled
together.
Find the probability that the average length of a randomly selected
bundle of steel rods is less than 162.6-cm.
P(¯xx¯ < 162.6-cm) =
B. A company produces steel rods. The lengths of the steel rods
are normally distributed with a mean of 246.8-cm and a standard...
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 167.1-cm and a standard
deviation of 0.6-cm. For shipment, 6 steel rods are bundled
together. Round all answers to four decimal places if
necessary.
What is the distribution of XX? XX ~ N( , )
What is the distribution of ¯xx¯? ¯xx¯ ~ N( , )
For a single randomly selected steel rod, find the probability
that the length is between 166.9-cm...
The weekly wages of steel workers at a steel plant are normally distributed with a mean...
The weekly wages of steel workers at a steel plant are normally
distributed with a mean weekly wage of $940 and a standard
deviation of $85. There are 1540 steel workers at this plant. a)
What is the probability that a randomly selected steel worker has a
weekly wage i) Of more than $850? ii) Between $910 and
$960? b) What percentage of steel workers have a weekly
wage of at most $820? c) Determine the total number of
steel...
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 195.2-cm and a standard
deviation of 0.8-cm. For shipment, 22 steel rods are bundled
together.
Find the probability that the average length of a randomly selected
bundle of steel rods is less than 195.1-cm.
P(M < 195.1-cm) =
Enter your answer as a number accurate to 4 decimal places. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are...
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 143.6-cm and a standard
deviation of 0.8-cm. For shipment, 41 steel rods are bundled
together. Round all answers to four decimal places if
necessary.
What is the distribution of X
? X
~ N(,)
What is the distribution of ¯x
? ¯x
~ N(,)
For a single randomly selected steel rod, find the probability
that the length is between 143.4-cm and 143.5-cm....
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Compare the MOSFET, JFET , and BJT and identify the reasons these devices behave differently. What...
- How would you use SAS Enterprise Miner to create a neural network model of your example?
- Explain the use of neural networking modeling in predictive analytics.
- Current Market Mix of Netflix, as detail as possible, please.
- This is all one question, thank you so much in advance! You must evaluate a proposal...
- X Company is considering the purchase of a new processor that costs $200,000. Shipping and setup...
- There are a large number of tasks involved in information technology and programming, and many of...
ADVERTISEMENT