Question

In: Physics

An average force of 10 N is exerted on a wagon through a 5.0 m distance....

An average force of 10 N is exerted on a wagon through a 5.0 m distance. The wagon has a mass of 2.0 kg.

a) What kinetic energy will the wagon gain?

b) What will be the final speed of the wagon?

Solutions

Expert Solution

Force exerted on wagon , F = 10 N

Distance = 5.0 m

mass of wagon = 2.0 kg

By Work-Energy theorem --

work done on the body by a Force ,F acting on it is equal to the change in kinetic energy

Gain in kinetic Energy

Gain in Kinetic Energy = Work done

= W

But W = Force x distance ( travelled by wagon )

= 10 N * 5 m

= 50 N.m

= 50 j

gain in kinetic energy by wagon = 50 j

--------------------------------------------------------------------------------------------------------------------------------------------------

We know that , KE = W

= 7.07m/s

Final speed of the wagon = 7.07m/s

-------------------------------------------------------------------------------------------------------------------------------------------------

The work donw by a force on a body equals change in KE

IT IS SHOWN BY NEWTON'S SECOND LAW.

F = ma

mass = mass of the body

a = acceleration

But, acceleration a =

s=distance reavelled by the body

Velocity increases from Vi to Vf

F= ma

multiply both sides by 's'

F= ma

we know W = FS

Therefore ,

mass is constant and velocity increases form Vf to Vi

THUS SHOWN

genius_generous answered 1 year ago

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