An Otto Cycle engine operation at cold-air standard has a volume of 0.1908 at the beginning...

An Otto Cycle engine operation at cold-air standard has a volume of 0.1908 at the beginning of isentropic compression. If the compression ratio is 12.5, how much heat is released from the fuel per kg of fuel burned if the fuel consumption is 0.02 kg/min? The mean effective pressure is 350kPa.

Solutions

Expert Solution

Explanation:

For Compression ratio = r = 12.5

Efficiency = 0.6359 =63.59%

swept volume = 0.175536 m³

m.e.p = (W.D/swept volume) => W.D/kg = 61443 N-m(J) = 61.443 kJ

Efficiency = W.D/Heat supply = >

0.6359 = 61.443/Qin

Qin = 96.625 kJ/kg

Qin/min = (mass flow of fuel in kg/min)*Qin in kJ/kg = (0.02 kg/min)*(96.625 kJ/kg)

Q_in = 1.9325 KJ/min

samet mamat answered 1 week ago

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