In FCC iron, carbon atoms are located at octahedral sites at the centre of each edge...

In FCC iron, carbon atoms are located at octahedral sites at the centre of each edge of the unit cell (1/2, 0, 0) and at the centre of the unit cell (1/2, 1/2, 1/2). In BCC iron, carbon atoms enter tetrahedral sites, such as (1/4, 1/2, 0). The lattice parameter is 0.3571nm for FCC iron and 0.2866nm for BCC iron. Assume that carbon atoms have a radius of 0.071nm.

(a) Would we expect a greater distortion of the crystal by an interstitial carbon in FCC or BCC iron?

(b) How is the distortion in FCC and BCC related to solubility of the interstitial carbon? Show your all work of calculation for a credit.

Expert Solution

Amanda K answered 6 months ago

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