In: Chemistry
The picture below shows two bulbs connected by a stopcock. The 6.00-L bulb contains nitric oxide at a pressure of 0.400 atm, and the 1.50-L bulb contains oxygen at a pressure of 2.50 atm. After the stopcock is opened, the gases mix and react: Determine which gases remain after the reaction goes to completion and calculate their partial pressures. The temperature at the beginnning and the end of the experiment is 22 °C. Which gases are present at the end of the experiment? What are the partial pressures of the gases? If the gas was consumed completely, put 0 for the answer.
Calculating the number of moles of Nitric Oxide
Calculating the number of moles of Oxygen
Initial 0.099 0.1548
Final 0 0.1053 0.099
Gases present in the mixture are NO2 and O2
All of the NO is consumed in the reaction
Pressure of the Container = (P1V1 + P2V2)/(V1+V2) = (6 * 0.4 + 2.5 * 1.50)/7.50
=> 0.82 atm
Partial Pressure of O2 = 0.1053/(0.1053+0.099) * 0.82 = 0.4226 atm
Partial Pressure of NO2 = 0.82 - 0.4226 = 0.397 atm