In: Math
Assuming the sample represents the population very well, that is, the population has approximately the same mean and same standard deviation.
a) 68% of the population fall between ___ inches and ___ inches
b) 95% of the population fall between ___ inches and ___ inches
c) 99.7% of the population fall between ___ inches and ___ inches
Height of 5 yr old Females | |
44.5 | |
45.4 | |
39.6 | |
45.5 | |
42 | |
44.5 | |
39.5 | |
42.3 | |
44 | |
37.7 | |
42.4 | |
43 | |
44.7 | |
43.3 | |
42.2 | |
37.6 | |
43.6 | |
44.6 | |
35.9 | |
34.6 | |
42.2 | |
43.4 | |
36.5 | |
41.2 | |
38.5 | |
42.2 | |
41.3 | |
40.5 | |
43.7 | |
42.4 | |
46.2 | |
44.7 | |
42.7 | |
40.5 | |
43.6 | |
40.3 | |
38.8 | |
37.4 | |
48.1 | |
42.7 | |
45.7 | |
38.6 | |
40.6 | |
44.4 | |
40.6 | |
48.5 | |
41.9 | |
44.5 | |
38.7 | |
47 | |
44.8 | |
41.6 | |
47.5 | |
42.6 | |
45 | |
41.6 | |
40.3 | |
40.7 | |
46 | |
42.8 | |
43.3 | |
50.2 | |
48.4 | |
42 | |
40.7 | |
41.7 | |
42.1 | |
38.2 | |
43.4 | |
39.9 | |
39.5 | |
46.9 | |
37.5 | |
40.3 | |
36.3 | |
38.9 | |
41.9 | |
42.6 | |
44.6 | |
42.3 |
Solution:
Assuming the sample represents the population very well, that is, the population has approximately the same mean and same standard deviation.
From given data, we have
Mean = 42.22375
SD = 3.13099
We know the empirical rule. It states as below:
About 68% of the population falls between 1 standard deviation from mean.
Mean – 1*SD = 42.22375 - 1*3.13099 = 39.09276
Mean + 1*SD = 42.22375 + 1*3.13099 = 45.35474
About 95% of the population falls between 2 standard deviation from mean.
Mean – 2*SD =42.22375 - 2*3.13099 =35.96177
Mean + 2*SD = 42.22375 + 2*3.13099 =48.48573
About 99.7% of the population falls between 3 standard deviation from mean.
Mean – 3*SD =42.22375 - 3*3.13099 =32.83078
Mean + 3*SD =42.22375 + 3*3.13099 = 51.61672
a) 68% of the population falls between 39.1 inches and 45.4 inches.
b) 95% of the population falls between 36.0 inches and 48.5 inches.
c) 99.7% of the population falls between 32.9 inches and 51.6 inches.