In: Economics
Consider the 2 cash flow options below at an interest rate of 10%
A | B | |
Initial Cost | 100,000 | 120,000 |
Year Cost 1 | 1000 | 1500 |
Year Cost 2 | 1400 | 1800 |
Year Cost 3 | 1800 | 2100 |
Year Cost 4 | 2200 | 2400 |
Year Cost 5 | 2600 | 2700 |
Year Cost 6 | 3000 | 3000 |
Year Cost 7 | 3400 | 3300 |
Year Cost 8 | 3800 | 3600 |
Year Cost 9 | 4200 | 3900 |
Year Cost 10 | 4600 | 4200 |
Year Cost 11 | 5000 | 4500 |
Year Cost 12 | 5400 | 4800 |
Year Cost 13 | 5800 | 5100 |
Year Cost 14 | 6200 | 5400 |
Year Cost 15 | 6600 | 5700 |
Option A stops at 15 years, while option B goes until year 30. The final year of option B is equal to 10200.
Yearly savings for option A is 10000 and for option B is 20000.
The salvage value for option A is 5000 and for option B is 12000.
Which option is better?
Option A:
Given, P = 100,000 , A1 = 1000 , G = 400 , n = 15 , Annual savings = 10000 , salvage value = 5000 , i =10%
Annual worth of option A = -100,000(A/P, 10%, 15) -[1000 + 400(A/G, 10%, 15)] + 10,000 + 5,000(A/F, 10%, 15)
= -100,000(0.1315) -[1000 + 400(5.279)] + 10,000 + 5,000(0.0315)
= -13,150 - 3,111.6 + 10,000 + 157.5
= $-6,104.1
Option B:
Given, P = 120,000 , A1 = 1500 , G = 300 , n = 20 , Annual savings = 20000 , salvage value = 12000 , i =10%
Annual worth of option B = -120,000(A/P, 10%, 20) -[1500 + 300(A/G, 10%, 20)] + 20,000 + 12,000(A/F, 10%, 20)
= -120,000(0.1175) -[1500 + 300(6.508)] + 20,000 + 12,000(0.0175)
= -14,100 - 3,452.4 + 20,000 + 210
= $2,657.6
Since the AW of option B is positive, therefore, option B is better.