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The gravitational potential is U(r) = − GMsmp/r d) r0 is the position of the minimum...

The gravitational potential is

U(r) = − GMsmp/r

d) r0 is the position of the minimum of the effective potential. What does this signify for the planet’s trajectory?

e) Taylor expand out the effective potential about r0. What is the period of oscillation for a small perturbation about r0?

f) Show that the period of small oscillation about r0 is the same as the orbital period.

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genius_generous answered 2 years ago
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