The figure shows a plot of potential energy U versus position x of a 0.250 kg...

The figure shows a plot of potential energy U versus position x of a 0.250 kg particle that can travel only along an x axis under the influence of a conservative force. The graph has these values: UA = 9.00 J, UC = 20.0 J and UD = 24.0 J. The particle is released at the point where U forms a “potential hill” of “height” UB = 12.0 J, with kinetic energy 8.00 J. What is the speed of the particle at (a)x = 3.50 m and (b)x = 6.50 m? What is the position of the turning point on (c) the right side and (d) the left side?

Expert Solution

genius_generous answered 2 years ago

The figure shows an approximate plot of stress versus strain for a spider-web thread, out to...

The figure shows an approximate plot of stress versus strain for a spider-web thread, out to the point of breaking at a strain of 2.05. The vertical axis scale is set by a = 0.130 GN/m2,b = 0.460 GN/m2, and c = 0.840 GN/m2. Assume that the thread has an initial length of 0.780 cm, an initial cross-sectional area of 8.00 × 10-12 m2, and (during stretching) a constant volume. The strain on the thread is the ratio of the...

The Lennard-Jones potential energy, U(x), is a function of "x" the distance between a pair of...

The Lennard-Jones potential energy, U(x), is a function of "x" the distance between a pair of molecules. It is frequently called the van der Walls potential between molecules for dipole-dipole interactions. The potential is U(x) = C12/ x^12 - C6/x^6 [1] Here we assume for water molecules: C12 = 9.5 x 104" J•m12 C6 = 1 x 10-76 J•m6. (a) What is the separation distance (Xs) between two water molecules where the applied force (F) to pull the molecules apart...

The figure shows angular position versus time graphs for six different objects. a) Rank these graphs on the basis of...

The figure shows angular position versus time graphs for six different objects.a) Rank these graphs on the basis of the angular velocity of each object. Rank positive angular velocities as larger than negative angular velocities. Rank from largest to smallest. To rank items as equivalent, overlap them.b) Rank these graphs on the basis of the angular acceleration of the object. Rank positive angular accelerations as larger than negative angular accelerations.Rank from largest to smallest. To rank items as equivalent, overlap...

make a plot of the data in the table below , plot position versus time time...

make a plot of the data in the table below , plot position versus time time squared (t2 ). make sure to label your graph properly.( Y axis title with units, X axis title with unit, title of the graph with equation , major tick marks. use data to plot the graph manually. use proper scal measurement position(m) time(s) time2 (s2 ) 1 0 0 0 2 5 1 1 3 21 2 4 4 46 3 9 5 82...

Find the energy spectrum of a particle in the infinite square well, with potential U(x) →...

Find the energy spectrum of a particle in the infinite square well, with potential U(x) → ∞ for |x| > L and U(x) = αδ(x) for |x| < L. Demonstrate that in the limit α ≫ hbar^2/mL, the low energy part of the spectrum consists of a set of closely-positioned pairs of energy levels for α > 0. What is the structure of energy spectrum for α < 0?

The Lennard-Jones potential energy, U(x), is a function of “x” the separation distance between a pair...

The Lennard-Jones potential energy, U(x), is a function of “x” the separation distance between a pair of atoms in a molecule. It is frequently called the van der Walls potential between atoms for dipole-dipole interactions. The potential is U(x) = C12/ x12 - C6/x6, [1] Where C12 = 1.51 x 10-134 J∙m12 C6 = 1.01 x 10-77 J∙m6. (a) Determine the shape of the potential energy curve vs. distance of separation (x) between the atoms using Equation [1] by plotting...

The pV diagram in (Figure 1) shows a cycle of a heat engine that uses 0.250...

The pV diagram in (Figure 1) shows a cycle of a heat engine that uses 0.250 mole of an ideal gas having γ=1.10. The curved part ab of the cycle is adiabatic. The internal energy of the gas changes by the following amounts: ΔUa→b=−2220J, ΔUb→c=−1.06×104J, and ΔUc→a=+1.29×104J. c=(0.002, 1.5) b=(0.009, 1.5) Part A: Find the pressure of the gas at point a. Express answers in pascals to three significant figures. Part B: How much heat enters this gas per cycle?...

What is the electric potential energy of the group of charges in the figure?

An electron is at the origin. (a) Calculate the electric potential VAat point A, x= 0.250...

An electron is at the origin. (a) Calculate the electric potential VAat point A, x= 0.250 cm. (b) Calculate the electric potential VBat point B, x= 0.750 cm. What is the potential difference VB- VA? (c) Would a negatively charged particle placed at point Anecessarily go through this same potential difference upon reaching point B? Explain.

A particle moves along the x axis. It is initially at the position 0.250 m, moving...

A particle moves along the x axis. It is initially at the position 0.250 m, moving with velocity 0.070 m/s and acceleration -0.250 m/s2. Suppose it moves with constant acceleration for 3.90 s. Assume it moves with simple harmonic motion for 3.90 s and x = 0 is its equilibrium position. (a) Find its position. (b) Find its velocity at the end of this time interval.

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