In: Statistics and Probability
In a survey of 1000 U.S. adults, 700 think police officers should be required to wear body cameras while on duty.
a. Construct a 90% confidence interval for the proportion of all U.S. adults that think police officers should be required to wear body cameras while on duty.
b. Interpret your confidence interval.
Solution :
Given that,
n = 1000
x = 700
= x / n = 700 / 1000 = 0.700
1 - = 1 - 0.700 = 0.300
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z0.05 = 1.645
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.645 * (((0.700 * 0.300) / 1000)
= 0.024
A 90% confidence interval for population proportion p is ,
- E < P < + E
0.700 - 0.024 < p < 0.700 + 0.024
0.676 < p < 0.724
(0.676 , 0.724)