Draw a diagram representing a spherical conductor in static equilibrium with an originally uniform electric field....

Draw a diagram representing a spherical conductor in static equilibrium with an originally uniform electric field.

How does charge density depend on the curvature of an object? Explain one practical application.

Calculate the electric field at one corner of a square 20 m on a side if the other three corners are occupied by 2.5 x 10-6 C charges.

Expert Solution

Diagram representing a spherical conductor in static equilibrium with an originally uniform electric field.

Dependence of charge density or curvature:

It is an observational fact that on a conducting surface, electric charge density is greater at those points where local surface curvature is also higher. For example, if some amount of charge is given to a needle, the charge density would be very high at the sharp tip of the needle. The surface curvature is also very high there, compared to the smoother cylindrical portions of the needle.

E = 107.67 N/C

genius_generous answered 2 years ago

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