1) When 2.69g of a nonelectrolyte solute is dissolved in water to make 655 mL of...

1) When 2.69g of a nonelectrolyte solute is dissolved in water to make 655 mL of solution at 23 C, the solution exerts an osmotic pressure of 877 torr.

What is the molar concentration of the solution?

How many moles of solute are in the solution?

What is the molar mass of the solute?

2) Biphenyl, C12H10, is a nonvolatile, nonionizing solute that is soluble in benzene, C6H6

At 25 ∘C, the vapor pressure of pure benzene is 100.84 Torr. What is the vapor pressure of a solution made from dissolving 12.9 g of biphenyl in 25.3 g of benzene?

Expert Solution

queen_honey_blossom answered 7 months ago

When 2.13 g of a nonelectrolyte solute is dissolved in water to make 395 mL of...

When 2.13 g of a nonelectrolyte solute is dissolved in water to make 395 mL of solution at 21 °C, the solution exerts an osmotic pressure of 959 torr. What is the molar concentration of the solution? How many moles of solute are in the solution? What is the molar mass of the solution?

When 2.14 g of a nonelectrolyte solute is dissolved in water to make 165 mL of...

When 2.14 g of a nonelectrolyte solute is dissolved in water to make 165 mL of solution at 22 °C, the solution exerts an osmotic pressure of 821 torr.

An unknown nonelectrolyte and nonvolatile compound is dissolved in enough pure water to make 348ml of...

An unknown nonelectrolyte and nonvolatile compound is dissolved in enough pure water to make 348ml of solution.The vapor pressure above the solution drops from 198.7mbar to 196.7mbar. When 100g of the compound is dissolved at constant temperature.Determine the molar mass of the unknown compound. Assume no change in volume occurs upon dissolution. The answer is 509 g/mol Why?

A) If 0.640 mol of a nonvolatile nonelectrolyte are dissolved in 3.60 mol of water, what...

A) If 0.640 mol of a nonvolatile nonelectrolyte are dissolved in 3.60 mol of water, what is the vapor pressure PH2O of the resulting solution? The vapor pressure of pure water is 23.8 torr at 25 ∘C . B) A solution is composed of 1.60 mol cyclohexane (P∘cy=97.6 torr) and 2.00 mol acetone (P∘ac=229.5 torr). What is the total vapor pressure Ptotal above this solution?

PART A If 0.480 mol of a nonvolatile nonelectrolyte are dissolved in 3.60 mol of water,...

PART A If 0.480 mol of a nonvolatile nonelectrolyte are dissolved in 3.60 mol of water, what is the vapor pressure PH2O of the resulting solution? The vapor pressure of pure water is 23.8 torr at 25 ∘C . Express your answer with the appropriate units. PART B A solution is composed of 1.90 mol cyclohexane (P∘cy=97.6 torr) and 2.30 mol acetone (P∘ac=229.5 torr). What is the total vapor pressure Ptotal above this solution?

If 0.580mol of a nonvolatile nonelectrolyte are dissolved in 3.50mol of water, what is the vapor pressure...

If 0.580mol of a nonvolatile nonelectrolyte are dissolved in 3.50mol of water, what is the vapor pressure PH2O of the resulting solution? The vapor pressure of pure water is23.8 torr at 25 ?C . In solutions composed of two liquids (A and B), each liquid contributes to the total vapor pressure above the solution. The total vapor pressure is the sum of the partial pressures of the components: --- A 2.500×10^-2M solution of NaCl in water is at 20.0?C. The sample...

16.636 g of a non-volatile solute is dissolved in 410.0 g of water. The solute does...

16.636 g of a non-volatile solute is dissolved in 410.0 g of water. The solute does not react with water nor dissociate in solution. Assume that the resulting solution displays ideal Raoult's law behaviour. At 90°C the vapour pressure of the solution is 517.01 torr. The vapour pressure of pure water at 90°C is 525.80 torr. The molar mass of the solute is 43.0 g/mol. Now suppose, instead, that 16.636 g of a volatile solute is dissolved in 410.0 g of...

9.537 g of a non-volatile solute is dissolved in 220.0 g of water. The solute does...

9.537 g of a non-volatile solute is dissolved in 220.0 g of water. The solute does not react with water nor dissociate in solution. Assume that the resulting solution displays ideal Raoult's law behaviour. At 25°C the vapour pressure of the solution is 23.498 torr. The vapour pressure of pure water at 25°C is 23.756 torr. Calculate the molar mass of the solute (g/mol). 71.1 g/mol Now suppose, instead, that 9.537 g of a volatile solute is dissolved in 220.0...

An unknown compound (152 mg) was dissolved in water to make 75.0 mL of solution. The...

An unknown compound (152 mg) was dissolved in water to make 75.0 mL of solution. The solution did not conduct electricity and had an osmotic pressure of 0.328 atm at 27°C. Elemental analysis revealed the substance to be 78.90% C, 10.59% H, and 10.51% O. Determine the molecular formula of this compound by adding the missing subscripts.

A sample containing acetaminophen was dissolved in water to make a 50.00-mL solution. The solution was...

A sample containing acetaminophen was dissolved in water to make a 50.00-mL solution. The solution was titrated with 0.5065 M NaOH, and the equivalence point was reached when 26.10 mL NaOH solution was added. The terminal hydrogen (on the OH) is removed during neutralization. The Ka value of acetaminophen is 3.2 × 10−10. Calculate the pH at the equivalence point.

Question