Question

In: Operations Management

The normal scrap loss for four successive operations is 5%, 3%, 15% and 10% respectively. How...

The normal scrap loss for four successive operations is 5%, 3%, 15% and 10% respectively. How many units should be started through in order to finish with 1,200 pieces? Find:


a) The total machine time needed if the operation times are 3, 6, 4, and 5 minutes, respectively.


b) The total cost if the cost per unit for each successive operation is $2, $5, $3, and $1, respectively.

Solutions

Expert Solution

operations

normal scrap loss

1-loss %

1

5%

95%

2

3%

97%

3

15%

85%

4

10%

90%

required output

         1,200

pieces

Output Required=Input Given *(1-Loss1%)*(1-Loss2%)*(1-Loss3%)*(1-Loss4%)

1200 = input *(1-0.05)*(1-0.03)*(1-0.15)*(1-0.10)

solve for input:

input = 1200/(95%*97%*85%*90%)

input

1702

pieces

(rounding off)

a)

operations

time/unit (min)

time

1

3

5107

2

6

9703

3

4

6275

4

5

6667

total time

27751

min

b)

operations

cost/unit

cost

1

$              2

$    3,404.51

2

$              5

$    8,085.71

3

$              3

$    4,705.88

4

$              1

$    1,333.33

total cost

$ 17,529.43

formulae used:


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