Question

How would you do the problem... What is the concentration in mmole/L of a Ca2+ solution that is 2.10 mEq/L ?

Answer 1

answer : 1.05 mmol / L

Ca+2 concentration = 2.10 mEq/L

                                 = 2.10 m   (mole /2L)

                                 = 1.05 mmol /L

clear explanation :

Normality = number of gram equivalents present in 1 litre solution

N = NEq / L

N = (W/ Eq ) / L

N = (W/Mw / L ) x n ------------------------>(1)

here Eq = Mw / n

Molarity = number of moles of solute present in 1 litre of solution

M = n / L

     = ( W / MW ) / L-------------------------(2)

from (1) and (2)

N = M x n

n = valency or charge

for this problem it is given in Normal we have to convert in molar . Ca+2 charge is 2 just divide the given value we get the answer.