Question

In: Physics

In a rectangular coordinate system, a positive point charge q = 7.50 nC is placed at...

In a rectangular coordinate system, a positive point charge q = 7.50 nC is placed at the point x= 0.180 m , y=0, and an identical point charge is placed at x= -0.180 m , y=0. Find the x and y components and the magnitude and direction of the electric field at the following points.

a. Find the x and y components of the electric field at the origin.

b. Find the magnitude of the electric field at the origin.

c. Find the x and y components of the electric field at x= 0.360 m , y=0.

d. Find the magnitude of the electric field at x= 0.360 m , y=0.

e. Find the direction of the electric field at x= 0.360 m , y=0.

f. Find the x and y components of the electric field at x= 0.180 m , y= -0.450 m .

g. Find the magnitude of the electric field at x= 0.180 m , y= -0.450 m .

h. Find the directiion of the electric field at x= 0.180 m , y= -0.450 m .

Solutions

Expert Solution

Electric field at due to a charge located at is

located at

----------------------------------

Electric field at Origin , due to is

Net electric field at origin is

a)X-component of electric field at origin is

b)Y-component of electric field at origin is

--------------------------------------

Electric field at x=0.360 ,y=0 , due to is

Electric field at , due to is

Net electric field at is

c)X-component of electric field at (0.360,0) is

Y-component of electric field at (0.360,0) is

d) Magnitude of electric field at (0.360,0) is

e) Direction of electric field at (0.360,0) is along Positive axis

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Electric field at x=0.180 ,y=-0.450 , due to is

Electric field at , due to is

Net electric field at is

f)X-component of electric field at (0.180,-0.450) is

Y-component of electric field at (0.180,-0.450) is

g) Magnitude of electric field at (0.180,-0.450) is

h) Direction of electric field at (0.180,-0.450) is counterclockwise with positive X-axis.

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genius_generous answered 1 year ago

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