In a rectangular coordinate system, a positive point charge 5.0nC is placed at x=2cm, y=0cm and...

In a rectangular coordinate system, a positive point charge 5.0nC is placed at x=2cm, y=0cm and a negative point charge -5.0nC is placed at x=-2cm,y=0cm. Point P is at x=2cm, y=3cm

K=8.99 x 10^9 (Nxm^2)/C^2

a) Calculate the magnitude of the force between the positive charge and negative charge

b) Draw the electric field vector at point P, caused by the positive charge. Find its magnitude

c) Draw the electric field vector at point P, caused by the negative charge. Find its magnitude

d) Determine the magnitude and direction of the net electric field vector at point P

e) If a charge q=-4.0nC with a mass 2.0 x 10^-6 kg is released from rest at point P, what is its acceleration?

f) Calculate the electric potential at point P

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Expert Solution

genius_generous answered 1 week ago

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