In: Statistics and Probability
A study of parental empathy for sensitivity cues and baby temperament (higher scores mean more empathy) was performed. Let x1 be a random variable that represents the score of a mother on an empathy test (as regards her baby). Let x2 be the empathy score of a father. A random sample of 35 mothers gave a sample mean of x1 = 67.17. Another random sample of 27 fathers gave x2 = 59.85. Assume that σ1 = 11.06 and σ2 = 11.13.
(a) Let μ1 be the population mean of x1 and let μ2 be the population mean of x2. Find a 95% confidence interval for μ1 – μ2. (Use 2 decimal places.)
lower limit | |
upper limit |
95% confidence interval for 1 - 2 is
(1 - 2 ) - Z * sqrt( 1 / n1 + 2 / n2) < 1 - 2 < (1 - 2 ) + Z * sqrt( 1 / n1 + 2 / n2)
(67.17 - 59.85) - 1.96 * sqrt( 11.062 / 35 + 11.132 / 27 ) < 1 - 2
< (67.17 - 59.85) + 1.96 * sqrt( 11.062 / 35 + 11.132 / 27 )
1.75 < 1 - 2 < 12.89
Lower limit = 1.75
Upper limit = 12.89