In: Physics
One possible means of achieving space flight is to place a perfectly reflecting aluminized sheet into Earth
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One possible means of achieving space flight is to place a
perfectly reflecting aluminized sheet into Earth 's orbit and to
use the light from the Sun to push this solar sail. Suppose such a
sail, of area 5.20 104 m2 and mass 6500 kg, is placed in orbit
facing the Sun. Ignore all gravitational effects, and assume a
solar intensity of 1340 W/m2.
(a) What force is exerted on the sail?
F = __?__ N
(b) What is the sail's acceleration?
a = __?__ m/s2
(c) How long does it take for this sail to reach the Moon, 3.84 108
m away?
t = __?__ days
Given:
The area of the sail, A = 5.20x104 m2
The mass of the sail, m = 6500 kg
The solar intensity, I = 1340 W/m2
The speed of the light, c = 3x108 m/s
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Solution:
a)
The radiation pressure is
P = 2I/c
= (2)(1340 W/m2)/(3x108 m/s)
= 893.33x10-8 N/m2
The force F realated with the The radiation pressure P is
F = PA
= (893.33x10-8 N/m2)(5.20x104 m2)
= 0.46453 N
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b)
According to Newton's second law of motion, the force
can be deffined as
F = ma
Therefore, the acceleration of
the sail's is
a = F/m
= (0.46453 N)/(6500 kg)
= 7.1467x10-5 m/s2
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c)
The distance, s = 3.84x108 m
Using the kinematic relation,
s = ut + (1/2)at2
s = 0 + (1/2)at2
Therefore, the time taken by the sail to reach the moon is
t = ?2s/a
= ?(2)(3.84x108 m)/(7.1467x10-5 m/s2)
= 3278150.188 s
= (3278150.188 s)(1 day/86400 s)
= 37.94 days
= 38.00 days (nearly)