Question

A 0.042 kg aluminum bullet traveling at 456 m/s strikes an armor plate and comes to a stop. If all its energy is converted to heat that is absorbed by the bullet, what is the bullet's temperature change in degrees Celsius? (This is a multi-step problem.)

Answer 1

Given data

mass of bullet m= 0.042 kg

velocity of bullet v= 456 m/s

now here energy conserved so the kinetic energy of the bullet is (k.e) is converted in to heat energy results the change in temperature of the bullet

so k.e= 1/2*m*v^2    => 1/2*0.042*456^2 =4366.656 J

                                                                = 4366.656*0.239 cal =1043.630 cal

now from the relation   dQ= m*C*dt      C is the specific heat of alluminium 0.22 Kcal/kg C= 220 cal/kg C

now change in temperature is   dt= dQ/m*C    => dt= 1043.630/(0.042*220) = 112.946 celcius