Sodium chloride (NaCl) exhibits predominantly ionic bonding. The Na+ and Cl- ions have electron structures that...

Sodium chloride (NaCl) exhibits predominantly ionic bonding. The Na⁺ and Cl^- ions have electron structures that are identical to which two inert gases?

Na⁺ has the same electron configuration as neon.

Cl^- has the same electron configuration as argon.

Na⁺ has the same electron configuration as argon.

Cl^- has the same electron configuration as xenon.

Na⁺ has the same electron configuration as xenon.

Cl^- has the same electron configuration as neon.

Expert Solution

The Na+ion is just a sodium atom that has lost one electron; therefore, it has an electron configuration the same as neon The Cl-ion is a chlorine atom that has acquired one extra electron;therefore, it has an electron configuration the same as argon. Na+ has the same electron configuration as neon. Cl- has the same electron configuration as argon.............. Answer is Ne and Ar............ Such a configuration is achieved to maximise stablization

queen_honey_blossom answered 2 years ago

The separation between neighboring Na+ and Cl- ions in crystal of NaCl is 0.281 nm, whilst...

The separation between neighboring Na+ and Cl- ions in crystal of NaCl is 0.281 nm, whilst the separation between neighboring Na ions in metallic sodium is 0.372 nm. Given that the ionic radius of Cl- is 0.181 nm, determine the radius of the Na+ ions in each case. Explain why the values are different.

Sodium chloride has a density of 2.17 g/cm3. What is the closest Na+...Cl- separation? Be sure...

Sodium chloride has a density of 2.17 g/cm3. What is the closest Na+...Cl- separation? Be sure your answer is given in picometers.

An aqueous solution containing sodium chloride (NaCl) and calcium chloride (CaCl2) is found to have a...

An aqueous solution containing sodium chloride (NaCl) and calcium chloride (CaCl2) is found to have a density of 1.043 g/mL. The results of an analysis indicate that the calcium concentration is 8.3 g/L and the sodium concentration is 12.2 g/L. What is the mole fraction of each component in this solution? Molar mass of Na = 22.99 g/mol Molar mass of Cl = 35.45 g/mol Molar mass of Ca = 40.078 g/mol

Sodium burns in chlorine to form sodium chloride, NaCl. How many grams of sodium Chloride will...

Sodium burns in chlorine to form sodium chloride, NaCl. How many grams of sodium Chloride will be formed when 1.8 grams of sodium is burned in 2.00 grams of Chlorine? what is the excess reactant in this reaction? what is the limiting reactant? how much excess reactant remains unreacted?

Give the full electron configuration for sodium (Na).

Give the full electron configuration for sodium (Na). electron configuration:

ASAP. I ) NaCl (s) = Na+ (aq) + Cl- (aq) ^^^What is the stress and...

ASAP. I ) NaCl (s) = Na+ (aq) + Cl- (aq) ^^^What is the stress and which direction should the equilibrium shift? III ) Fe+3(aq) + SCN-(aq) = Fe(SCN)+2(aq) ^^^What is the stress and which direction should the equilibrium shift IV) 2CrO4 –2(aq) + 2H+ (aq) = Cr2O7 –2(aq) + H2O(l) ^^^What is the stress and which direction should the equilibrium shift?

The Goldman Equation K+, Na+ and Cl- ions concentrations Changing the ratio of one of...

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Why is NaCl added to icy roads? a) It causes the Na+ ions to cluster together....

Why is NaCl added to icy roads? a) It causes the Na+ ions to cluster together. b) The NaCl keeps the ice from melting c) The coating provides traction for tires. D) It lowers the freezing point of water. 36. Molecules whose water solutions conduct electric current ______________. a) are nonpolar b) ionize in water c) do not dissolve in water d) decompose in water 37. Which of the following does NOT increase the rate at which a solid dissolved...

Identify the bonding in each of the following substances as ionic or covalent. (a) NaCl (select)ioniccovalent...

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Arrange these ions in order of increasing ionic radius: K+, P3– , S2– , Cl– ....

Arrange these ions in order of increasing ionic radius: K+, P3– , S2– , Cl– . Increasing radius  A) K+ < Cl– < S2– < P3– D) Cl– < S2– < P3– < K+ B) K+ < P3– < S2– < Cl– E) Cl– < S2– < K+ < P3– C) P3– < S2– < Cl– < K+ Reasoning:

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