Question

Create a Guess the Number game.

• Python randomly chooses a secret four-digit number (with no repeating digits) and asks the user to guess it.
• The user has up to ten attempts to guess the number. After each guess, Python gives the user two clues (until the user either guesses the number correctly or runs out of attempts):
  • The number of digit(s) in the user’s guess that is (are) both correct and in the right position.
  • The number of digit(s) in the user’s guess that is (are) correct but in the wrong position.
    • For example, say the secret number is 0123.
      • If the user’s guess is 4567, the clues will be:
        • Right digit and position: 0
        • Right digit but wrong position: 0
      • If the user’s guess is 1023, the clues will be:
        • Right digit and position: 2
        • Right digit but wrong position: 2
• If the user guesses the correct number within his/her ten attempts, the game will finish.
• If the user fails to guess the correct number within his/her ten attempts, the number will be shown and the game will finish.
• When the game finishes (i.e., whether the user guesses the correct number or fails to do so in ten attempts), Python asks the user whether he/she wants to continue playing.
  • If the user enters “Y” he/she will play another round. If the user enters “N” the game will end
• PLEASE USE LOW-LEVEL PYTHON LANGUAGE SUCH AS WHILE LOOP OR IF ELSE ARGUMENTS, TRY NOT TO MAKE IT TOO ADVANCED

Answer 1

Answer:

Here is the python code as per your requirement

Raw code:

#Code to generate secret number with four unique digits

import random

#user to ask if he want's to paly again after 10

tryAgain='Y'

#While loop

while (tryAgain!='N'):

#digits

digts='0123456789'

#secret string

secret=''

#iterating while loop till the string legth is 4

while(len(secret)<4):

#get the random number from digts string

num=random.choice(digts)

#if that digt is already in secret string don't do anything

if num in secret:

continue

#or else concatnate the string to secret

else:

secret=secret+num

#count initialized to 0

count=0

#to give chances 10 attempts

while(count<10):

#declaring variables to conoutn right postions at right index and right values and not right indexes

right_pos_num_count=0

right_num_nopos_count=0

#asking the user to enter guess

guess=input("Guess: ")

#iterate over the guess

for i in range(len(guess)):

#iterate over the secretn

for j in range(len(secret)):

#checking the position and index

if i==j and guess[i]==secret[j]:

#if both are same increment the count

right_pos_num_count+=1

#if positions are same and indexes aren't

if guess[i]==secret[j] and i!=j:

right_num_nopos_count+=1

#print the hints

print('Right digit and position: ',right_pos_num_count)

print('Right digit but wrong position: ',

right_num_nopos_count)

#if user guess right

if right_pos_num_count==4:

#print this and break the loop of 10

print('Congratulations you Guessed it right!')

break

#else incremnt the count of attempts

else:

count+=1

#ask the user if he wants to play again

tryAgain=input('wants to continue playing? (Y | N): ').upper()

Editor:

output:

Hope this helps you! If you still have any doubts or queries please feel free to comment in the comment section.

"Please refer to the screenshot of the code to understand the indentation of the code".

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