In: Economics
A large manufacturing company is now evaluating three mutually exclusive production systems. The following table describes the data:
| 
 System  | 
 A  | 
 B  | 
 C  | 
| 
 Initial investment (millions)  | 
 $2,005  | 
 $8,800  | 
 $19,000  | 
| 
 Annual receipts less expenses (millions)  | 
 $ 600  | 
 $1,500  | 
 $ 2,300  | 
| 
 Salvage value (millions)  | 
 $15  | 
 $100  | 
 $330  | 
| 
 Useful life (years)  | 
 5  | 
 10  | 
 20  | 
Apply repeatability assumption and use the AW method to select the best system. The MARR is 10% per year, and the system chosen must provide service for 20 years. (correct your final answer to 3 decimal places)
MARR = 10% per year
For Type - A:
Useful life = 5 years
From the compound interest table, we obtain
(A/P, 10%, 5) = 0.2638
(A/F, 10%, 5) = 0.1638
Intial investment = -$2,005 million
Annual net receipts = $600 million
Salvage Value = $15 million
Annual worth of the Type - A system = AW of the initial investment + Annual net receipts + AW of the salvage value
= -$2,005 million (A/P, 10%, 5) + $600 million + $15 million (A/F, 10%, 5)
= -$2,005 million * 0.2638 + $600 million + $15 million * 0.1638
= $73.538 million
For Type - B:
Useful life = 10 years
From the compound interest table, we obtain
(A/P, 10%, 10) = 0.1627
(A/F, 10%, 10) = 0.0627
Intial investment = -$8,8000 million
Annual net receipts = $1,500 million
Salvage Value = $100 million
Annual worth of the Type - B system = AW of the initial investment + Annual net receipts + AW of the salvage value
= -$8,800 million (A/P, 10%, 10) + $1,500 million + $100 million (A/F, 10%, 10)
= -$8,800 million * 0.1627 + $1,500 million + $100 million * 0.0627
= $74.510 million
For Type - C:
Useful life = 20 years
From the compound interest table, we obtain
(A/P, 10%, 20) = 0.1175
(A/F, 10%, 20) = 0.0175
Intial investment = -$19,0000 million
Annual net receipts = $2,300 million
Salvage Value = $330 million
Annual worth of the Type - C system = AW of the initial investment + Annual net receipts + AW of the salvage value
= -$19,000 million (A/P, 10%, 20) + $2,300 million + $330 million (A/F, 10%, 20)
= -$19,000 * 0.1175 + $2,300 million + $330 million * 0.0175
= $73.275 million
As the AW of type - B production system is the highest among the given alternatives, select type- B production system.