Question

In: Economics

Consider the Solow growth model with population growth and growth in the efficiency of labor. Suppose...

  1. Consider the Solow growth model with population growth and growth in the efficiency of labor. Suppose that 2 countries A and B have the same production function given by Yt = Ktα(LtEt)1−α, the same rate of growth of E (g), the same depreciation rate of physical capital (δ) and the same saving rate s. The initial level of E, E0, is lower in country A than in country B.

    1. (a) Compare the steady-state levels of output per effective worker of these two coun- tries.

    2. (b) Assume now that at time 0 both countries are above the steady state and that k0A = k0B (i.e., the level of capital per effective worker at time 0 is the same in both countries) and continue to assume that the initial level of E is higher in country B than in country A. Draw log of output per capita for these two countries as a function of time (have time on the x-axis) starting in period 0 and show how they both converge to their respective balanced growth paths.

    3. (c) Do these countries converge to each other in output per capita? Defend your answer.

Solutions

Expert Solution

Given: Yt = Ktα(LtEt)1−α

Et+1 = (1 + g)Et

depreciation rate of physical capital = δ)

saving rate = s.

assuming growth in labor, n = 0 (since not given in the question)

Output per effective worker: yt ≡ Yt/LtEt ,

Capital per effective worker: kt ≡ Kt/LtEt ,

Consumption per effective worker: ct =Ct/LtEt

Investment per effective worker: it ≡ It/LtEt .

Yt = Ktα(LtEt)1−α, therefore,  Yt/LtEt = ( Kt/LtEt )α ⇒ yt = ktα

Ct = (1 − s)Yt

Ct/LtEt = (1 − s) Yt/LtEt,

ct = (1 − s)yt = (1 − s)ktα

It = sYt

It/LtEt = s Yt/LtEt

it = syt = sktα (Capital gain)

Capital loss = (n+g +δ)kt =  (g +δ)kt (since n=0)

Law of motion states that: change in capital stock (net capital stock), ∆kt = capital gain - capital loss = kt+1 − kt

∆kt = it − (g + δ)kt = sktα − (n + g + δ)kt

If, it < (g + δ)kt ⇒ ∆kt < 0

it = (g + δ)kt ⇒ ∆kt = 0 (steady-state)

it > (g + δ)kt ⇒ ∆kt > 0

Now, at steady state: it = (n + g + δ)kt or skssα = (g + δ)kss

or solving for kss = [ s / (g + δ) ] 1/1−α, where kss = steady-state capital per effective worker.

Since, s, g, δ and α is same for both countries, and steady-state level depends only on these factors, therefore, both countries will have same level of steady-state capital per effective worker and output per effective worker.

b) yt = Yt/EtLt or yt = [(Yt/Lt)/Et]

taking log both sides, we get,

logyt = log (Yt/Lt) - Log(Et)

differentiating w.r.t. to time t, we get

(1/yt)dyt/dt = d(log (Yt/Lt)/dt - (1/Et)dEt/dt

since at steady-state, LHS = 0, and (1/Et)dEt/dt = g, we get

d(log (Yt/Lt)/dt = g, if an economy is at steady state, than the output per workers grows at rate g.

Given at time 0, both countries are above the steady state and that k0A = k0B such that k0A > kss and k0B > kss

now, k0A = k0B, this implies, [(K/L)/E]0A = [(K/L)/E]0B

If EA < EB then (K/L)0A < (K/L)0B to maintain the equality.

therefore, Country B will have higher output per worker than Country A at steady state.

the transition graph will look like following

c) The countries will converge to same output per effective worker but not to same output per capita.

yt = Yt/(LtEt) or Yt/Lt = yt*E. We know that yss will be the same in both countries, but that EB>EA.

Therefore yss*EB>yss EA

This implies that (Y/L)B > (Y/L)A.

Thus, Country B will have higher output per worker than Country A at steady state as explained in part (b).


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