Question
In: Math
Paired sample test, (1) construct a 95% confidence interval and (2) conduct a t-test (α =...
Paired sample test, (1) construct a 95% confidence interval and (2) conduct a t-test (α = 5%). This is to report to the NFL commisioner regarding points scored vs points allowed.
Data sets below
| Team | Points Scored | Points Allowed |
| Los Angeles | 463 | 429 |
| Seattle | 452 | 271 |
| Indianapolis | 439 | 247 |
| New Orleans | 435 | 398 |
| NY Gants | 422 | 314 |
| Cincinnati | 421 | 350 |
| San Diego | 418 | 312 |
| Philadelphia | 410 | 388 |
| Kansas City | 403 | 325 |
| Tennessee | 399 | 421 |
| Green Bay | 398 | 344 |
| Denver | 395 | 258 |
| Carolina | 391 | 259 |
| Pittsburg | 389 | 258 |
| New England | 379 | 338 |
| Buffalo | 371 | 367 |
| Minnesota | 366 | 344 |
| Houston | 365 | 431 |
| Jacksonville | 361 | 269 |
| Washington | 359 | 293 |
| Atlanta | 351 | 341 |
| Arizona | 342 | 387 |
| Dallas | 325 | 308 |
| Miami | 318 | 317 |
| Tampa Bay | 300 | 274 |
| Oakland | 290 | 383 |
| Baltimore | 265 | 299 |
| Chicago | 260 | 202 |
| Detroit | 254 | 345 |
| NY Jets | 240 | 355 |
| San Francisco | 239 | 228 |
| Cleveland | 232 | 301 |
Solutions
Expert Solution
| Team | Points Scored | Points Allowed | Difference(d) |
| Los Angeles | 463 | 429 | 34 |
| Seattle | 452 | 271 | 181 |
| Indianapolis | 439 | 247 | 192 |
| New Orleans | 435 | 398 | 37 |
| NY Gants | 422 | 314 | 108 |
| Cincinnati | 421 | 350 | 71 |
| San Diego | 418 | 312 | 106 |
| Philadelphia | 410 | 388 | 22 |
| Kansas City | 403 | 325 | 78 |
| Tennessee | 399 | 421 | -22 |
| Green Bay | 398 | 344 | 54 |
| Denver | 395 | 258 | 137 |
| Carolina | 391 | 259 | 132 |
| Pittsburg | 389 | 258 | 131 |
| New England | 379 | 338 | 41 |
| Buffalo | 371 | 367 | 4 |
| Minnesota | 366 | 344 | 22 |
| Houston | 365 | 431 | -66 |
| Jacksonville | 361 | 269 | 92 |
| Washington | 359 | 293 | 66 |
| Atlanta | 351 | 341 | 10 |
| Arizona | 342 | 387 | -45 |
| Dallas | 325 | 308 | 17 |
| Miami | 318 | 317 | 1 |
| Tampa Bay | 300 | 274 | 26 |
| Oakland | 290 | 383 | -93 |
| Baltimore | 265 | 299 | -34 |
| Chicago | 260 | 202 | 58 |
| Detroit | 254 | 345 | -91 |
| NY Jets | 240 | 355 | -115 |
| San Francisco | 239 | 228 | 11 |
| Cleveland | 232 | 301 | -69 |
| Total | 1096 |
Sample size = n = 32
Sample mean = 
= 34.25
Standard deviation = Sd = 77.850
Level of confidence interval is 0.95
Formula for confidence interval is
Degrees of freedom = n - 1 = 32 - 1 = 31
tc = 2.040 ( Using t table)
milcah answered 7 months agoRelated Solutions
Construct a 95% confidence interval for an experiment that found the sample mean temperature for a...
Construct a 95% confidence interval for an experiment
that found the sample mean temperature for a certain city in August
was 101.82, with a population standard deviation of 1.2. There were
6 samples in this experiment.
A group of 10, foot - surgery patients had a mean
weight of 240 pounds. The sample standard deviation was 25 pounds.
Find a confidence interval for a sample for the true mean weight of
all foot – surgery patients. Find a 95% Confidence...
Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the...
Use the standard normal distribution or the t-distribution to
construct a 95% confidence interval for the population mean.
Justify your decision. If neither distribution can be used,
explain why. Interpret the results. In a random sample of 17
patients at a hospital's minor emergency department, the mean
waiting time before seeing a medical professional was 14 minutes
and the standard deviation was 9 minutes. Assume the waiting times
are not normally distributed. Which distribution should be used to
construct the...
Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the...
Use the standard normal distribution or the t-distribution to
construct a 95% confidence interval for the population mean.
Justify your decision. If neither distribution can be used,
explain why. Interpret the results. In a random sample of 47
people, the mean body mass index (BMI) was 27.7 and the standard
deviation was 6.02. Which distribution should be used to construct
the confidence interval? Choose the correct answer below:
Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the...
Use the standard normal distribution or the t-distribution to
construct a 95% confidence interval for the population mean.
Justify your decision. If neither distribution can be used,
explain why. Interpret the results. In a random sample of 18
mortgage institutions, the mean interest rate was 3.49% and the
standard deviation was 0.48%. Assume the interest rates are
normally distributed. Which distribution should be used to
construct the confidence interval? A. Use a normal distribution
because nless than30 and the interest...
Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the...
Use the standard normal distribution or the t-distribution to
construct a
95%
confidence interval for the population mean. Justify your
decision. If neither distribution can be used, explain why.
Interpret the results. In a random sample of
12
mortgage institutions, the mean interest rate was
3.48%
and the standard deviation was
0.32%.
Assume the interest rates are normally distributed.
Which distribution should be used to construct the confidence
interval?
A.Use a t-distribution because the interest rates are normally
distributed and...
How do you construct a confidence interval for a t test and a z test?
How do you construct a confidence interval for a t test and a z
test?
Construct a 95% confidence interval to estimate the population proportion with a sample proportion equal to...
Construct a 95% confidence interval to estimate the population
proportion with a sample proportion equal to
0.45 and a sample size equal to 120.
----- A 95% confidence interval estimates that the population
proportion is between a lower limit of
___ and an upper limit of ___
????
Construct a 95% confidence interval for the population standard deviation of a random sample of 15...
Construct a 95% confidence interval for the population standard
deviation of a random sample of 15 crates which have a mean weight
of 165.2 points and a standard deviation of 12.9 pounds. Assume the
population is normallyn distributed.
A. 9.9, 18.8
B. 9.4, 20.3
Please show work.
1)For the following PAIRED OBSERVATIONS, calculate the 95% confidence interval for the population mean mu_d: A...
1)For the following PAIRED OBSERVATIONS, calculate the 95%
confidence interval for the population mean mu_d: A = {24.83,
24.84, 24.53}, B = {11.94, 13.07, 9.97}.
choose the correct answer
7.24 < mu_d < 18.91
9.98 < mu_d < 16.17
13.05 < mu_d < 13.09
9.59 < mu_d < 16.56
6.98 < mu_d < 19.17
11.79 < mu_d < 14.36
6.90 < mu_d < 19.25
10.62 < mu_d < 15.53
7.55 < mu_d < 18.59
12.27 < mu_d < 13.88
2)For...
What sample size would be needed to construct a 95% confidence interval with a 3% margin...
What sample size would be needed to construct a 95% confidence
interval with a 3% margin of error on any population
proportion?
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Holly bought a 7-year bond, with a 3% coupon paid semi annually. It was priced to...
- METAR Abbreviations METAR (Meteorological Aviation Report) is a format for reporting weather information, either for pilots...
- The data below are the heights of fathers and sons (inches). There are 8 rows in...
- Without quantization procedure how much of actual information is lost during analog to digital conversion process??...
- 11. Suppose that a 32M × 16 memory built using 512K × 8 RAM chips and...
- Write a C++ program that asks the user to enter in three numbers and displays the...
- Economist Steven Landsburg argues that if one believes in the death penalty for murderers because of...
ADVERTISEMENT