Question

Write a console application to total a set of numbers indicated and provided by a user, using a while loop or a do…while loop according to the user’s menu choice as follows:

C++programming

Menu

1. To total numbers using a while loop

2. To total numbers using a do...while loop

Enter your menu choice: 1

How many numbers do you want to add: 2

Enter a value for number 1: 4

Enter a value for number 2: 5

The total is: 9

Example

Menu

1. To total numbers using a while loop

2. To total numbers using a do...while loop.

Enter your menu choice: 1

How many numbers do you want to add: 4

Enter a value for number 1: 3

Enter a value for number 2: 2

Enter a value for number 3: 5

Enter a value for number 4: 1

The total is: 11

Requirements

1. All the values above are only examples.

2. Menu choice 1 will total numbers provided by the user using a while loop.
3. Menu choice 2 will total numbers provided by the user using a do…while loop.
4. The message “Enter a value for number #” must include a sequence number (i.e. 1, 2, 3, 4, 5, 6, …).

Answer 1

Program:

#include <iostream>

using namespace std;

int
main ()
{
  int menuChoice, numbersCount;
  // Display menu
  cout << "Menu" << endl;
  cout << "1. To total numbers using a while loop" << endl;
  cout << "2. To total numbers using a do...while loop" << endl;
  // Take input for menu choice
  cout << "Enter menu choice: ";
  cin >> menuChoice;
  // Take input for how many numbers to be added
  cout << "How many numbers do you want to add: ";
  cin >> numbersCount;
  
  int arr[numbersCount];
  // Take input for numbers and add them to an array
  for (int i = 0; i < numbersCount; ++i) {
      cout << "Enter a value for number " << i+1 << ": ";
      cin >> arr[i];
  }
  // condition to check the menu choice is 1
  if (menuChoice == 1) {
      int sum = 0;
      int n = 0;
      // Sum the numbers using while loop
      while(n < numbersCount) {
                sum += arr[n];
                n++;
      }
      // Printing the sum of the elements
      cout << "The total is: " << sum;
  }
  // condition to check the menu choice is 2
  else if (menuChoice == 2) {
      int sum = 0;
      int n = 0;
      // Sum the numbers using do...while loop
      do {
        sum += arr[n];
                n++;
      }
    while (n < numbersCount);
    // Printing the sum of the elements
    cout << "The total is: " << sum;
  }

  return 0;
}

Output: