In: Math
Researchers watched groups of dolphins off the coast of Ireland in
1998 to determine what activities the dolphins partake in at
certain times of the day ("Activities of dolphin," 2013). The
numbers in Table 3 represent the number of groups of dolphins that
were partaking in an activity at certain times of days. Is there
enough evidence to show that the activity and the time period are
independent for dolphins? Why or Why not? Test at the 1% level.
Activity | Morning | Noon | Afternoon | Evening | Row Total |
Travel | 6 | 6 | 14 | 13 | 39 |
Feed | 28 | 4 | 0 | 56 | 88 |
Social | 38 | 5 | 9 | 10 | 62 |
Column Total | 72 | 15 | 23 | 79 | 189 |
Ans:
H0:the activity and the time period are independent for dolphins.
Ha:the activity and the time period are dependent for dolphins.
Observed(fo) | |||||
Activity | Morning | Noon | Afternoon | Evening | Row Total |
Travel | 6 | 6 | 14 | 13 | 39 |
Feed | 28 | 4 | 0 | 56 | 88 |
Social | 38 | 5 | 9 | 10 | 62 |
Column Total | 72 | 15 | 23 | 79 | 189 |
Expected(fe) | |||||
Activity | Morning | Noon | Afternoon | Evening | Row Total |
Travel | 14.86 | 3.10 | 4.75 | 16.30 | 39 |
Feed | 33.52 | 6.98 | 10.71 | 36.78 | 88 |
Social | 23.62 | 4.92 | 7.54 | 25.92 | 62 |
Column Total | 72 | 15 | 23 | 79 | 189 |
Chi square=(fo-fe)^2/fe | |||||
Activity | Morning | Noon | Afternoon | Evening | Row Total |
Travel | 5.28 | 2.73 | 18.04 | 0.67 | 26.72 |
Feed | 0.91 | 1.28 | 10.71 | 10.04 | 22.93 |
Social | 8.76 | 0.00 | 0.28 | 9.77 | 18.81 |
Column Total | 14.95 | 4.00 | 29.03 | 20.48 | 68.46 |
Test statistic:
Chi square=68.46
df=(3-1)*(4-1)=6
alpha=0.01
critical chi square value=CHIINV(0.01,6)=16.812
As,test statistic chi square is greater than critical chi square value,so reject the null hypothesis.
There is not enough evidence to conclude that the activity and the time period are independent for dolphins.