Let N(n) be the number of all partitions of [n] with no singleton blocks. And let...

Let N(n) be the number of all partitions of [n] with no singleton blocks. And let A(n) be the number of all partitions of [n] with at least one singleton block. Prove that for all n ≥ 1, N(n+1) = A(n). Hint: try to give (even an informal) bijective argument.

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Colby Messinger answered 1 year ago

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