Question

Given the definition for a Point class that holds the coordinates of the point as double values x and y, write a function called pt_dist that takes two points and returns the straight-line distance between them (as a double). Use two ways, pt_dist function version and the pt_dist method version. In main, include two if else tests for each, If passed "TEST PASSED, DIST IS " else "Test Failed, dist is ".

Hint: Rhymes with Bythagorean Beorem.

#include <iostream>
#include <cmath>
using namespace std;

// given point class
class Point
{
public:
   double x, y;
};

// put your function here, and name it pt_dist

//method version

int main() {
   return 0;
}

Answer 1

HI, Please find my implementation

Please let me know in case of any issue.

#include <iostream>
#include <cmath>
using namespace std;
// given point class
class Point
{
public:
double x, y;
// method declaration
double pt_dist(Point &other);
};
// put your function here, and name it pt_dist
double pt_dist(Point &first, Point &second){
    return sqrt((first.x - second.x)*(first.x - second.x) + (first.y - second.y)*(first.y - second.y));
}

//method version
double Point::pt_dist(Point &other){
    return sqrt((other.x - x)*(other.x - x) + (other.y - y)*(other.y - y));
}

int main() {

   // creating two objects
   Point p1;
   p1.x = 3;
   p1.y = 4;

   Point p2;
   p2.x = 8;
   p2.y = 9;

   double dist1 = p1.pt_dist(p2);
   double dist2 = pt_dist(p1, p2);

   cout<<"Distance: "<<dist1<<endl;
   if(dist1 == dist2){
       cout<<"TEST PASSED, DIST IS"<<endl;
   }
   else{
       cout<<"TEST Failed, DIST IS"<<endl;
   }
return 0;
}