In: Statistics and Probability
Thirty-two small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 40.5 cases per year.
(a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
lower limit | |
upper limit | |
margin of error |
(b) Find a 95% confidence interval for the population mean annual
number of reported larceny cases in such communities. What is the
margin of error? (Round your answers to one decimal place.)
lower limit | |
upper limit | |
margin of error |
(c) Find a 99% confidence interval for the population mean annual
number of reported larceny cases in such communities. What is the
margin of error? (Round your answers to one decimal place.)
lower limit | |
upper limit | |
margin of error |
Part a)
Confidence Interval :-
Lower Limit =
Lower Limit = 126.7237
Upper Limit =
Upper Limit = 150.2763
90% Confidence interval is ( 126.7 , 150.3 )
Margin of Error =
Part b)
Confidence Interval :-
Lower Limit =
Lower Limit = 124.4677
Upper Limit =
Upper Limit = 152.5323
95% Confidence interval is ( 124.5 , 152.5 )
Margin of Error =
Part c)
Confidence Interval :-
Lower Limit =
Lower Limit = 120.0585
Upper Limit =
Upper Limit = 156.9415
99% Confidence interval is ( 120.1 , 156.9 )
Margin of Error =