Question

In: Statistics and Probability

Survival Organ 124 Stomach 42 Stomach 25 Stomach 45 Stomach 412 Stomach 51 Stomach 1112 Stomach...

Survival Organ
124 Stomach
42 Stomach
25 Stomach
45 Stomach
412 Stomach
51 Stomach
1112 Stomach
46 Stomach
103 Stomach
876 Stomach
146 Stomach
340 Stomach
396 Stomach
81 Bronchus
461 Bronchus
20 Bronchus
450 Bronchus
246 Bronchus
166 Bronchus
63 Bronchus
64 Bronchus
155 Bronchus
859 Bronchus
151 Bronchus
166 Bronchus
37 Bronchus
223 Bronchus
138 Bronchus
72 Bronchus
245 Bronchus
248 Colon
377 Colon
189 Colon
1843 Colon
180 Colon
537 Colon
519 Colon
455 Colon
406 Colon
365 Colon
942 Colon
776 Colon
372 Colon
163 Colon
101 Colon
20 Colon
283 Colon
1234 Ovary
89 Ovary
201 Ovary
356 Ovary
2970 Ovary
456 Ovary
1235 Breast
24 Breast
1581 Breast
1166 Breast
40 Breast
727 Breast
3808 Breast
791 Breast
1804 Breast
3460

Breast

719 Breast

Conlumn 1. Survival: The survival time of the patient in days

Column 2. Organ: the organ where cancer was present

- stomach. Bronchus. Colon, Ovary, Breast

(a)Create a groupn plot of Survival by organ type. Does there aooear to be significant differences in the groups? Explain your anwer.

(b) Find the sample average of survival by organ type. Do you believe you woulf reject the null hypothesis of single factor anova based on these values? Explain.

(c) Do you believe the standard deviations of each population are equal? explain.

(d) What level of alpha would you suggest if concluding that the true average survival time was equal when in reality it was not, would be considered the most severe error?

II. Continue with problem I.

(a) Find the value of SSTO, SSA, SSE.

(b) Find the value of MSTO, MSA, MSE.

(C) Find the value of the test statistic, and the corresponding p value.

(D) State your conclusion in terms of the problem if alpha is equal 0.05.

Please show the process, need help! Thank you

Solutions

Expert Solution

Answer:

Based on the given data:

Survival Survival Survival Survival Survival
Stomach   Bronchus Colon Ovary Breast
124 81 248 1234 1235
42 461 377 89 24
25 20 189 201 1581
45 450 1843 356 1166
412 246 180 2970 40
51 166 537 456 727
1112 63 519 3808
46 64 455 791
103 155 406 1804
876 859 365 3460
146 151 942 719
340 166 776
396 37 372
223 163
138 101
72 20
245 283
Average 286.00 211.59 457.41 884.33 1395.91
Std dev. 346.31 209.86 427.17 1098.58 1238.97

(a) Create a group plot of Survival by organ type. Does there appear to be significant differences in the groups? Explain your answer.

Error bars represents standard deviation

Based on the survival plot by organ type, it appears that survival time is significantly different in different groups.

b) Find the sample average of survival by organ type. Do you believe you would reject the null hypothesis of single factor Anova based on these values? Explain.

Mean of the sample is calculated using the formula:

Standard deviation of the sample is calculated using the formula:

Survival by Organ type
Organ Mean Std dev.
Stomach   286.0 346.3
Bronchus 211.6 209.9
Colon 457.4 427.2
Ovary 884.3 1098.6
Breast 1395.9 1239.0

The mean values differ significantly among different organs, standard deviation also varies a lot by each organ type. Based on the average value of survival days for different organs, it appears that there is significant difference in the mean survival time of the patient depending on the organ affected by cancer.

(c) Do you believe the standard deviations of each population are equal? explain.

  • Based on the data analysis, the standard deviations of the sample varies a lot. The population variance of the survival time of patients. for different groups (based on the organ affected) seems to be unequal.

(d) What level of alpha would you suggest if concluding that the true average survival time was equal when in reality it was not, would be considered the most severe error?

Significance level 0.01

II. Continue with problem I.

(a) Find the value of SSTO, SSA, SSE.

(b) Find the value of MSTO, MSA, MSE.

(C) Find the value of the test statistic, and the corresponding p value.

(D) State your conclusion in terms of the problem if alpha is equal 0.05.

Organ Stomach   Bronchus Colon Ovary Breast
Group no. 1 2 3 4 5 Total
N 13 17 17 6 11 64
3718 3597 7776 5306 15355 35752
Mean 286.0 211.6 457.4 884.3 1395.9 558.6
2502512 1465733 6476402 10726650 36784569 57955866
Variance 119930.333 44040.6324 182473.0074 1206875.467 1535038.491 602919.127
Std. Dev 346.31 209.86 427.17 1098.58 1238.97 776.48
Std. Err 96.049 50.90 103.60 448.49 373.56 97.06
Source SS df MS
Between 11535760.52 4 2883940.131
Within 26448144.48 59 448273.6352
Total 37983905 63
F Fcritical p-value
6.43 2.53 0.0002 Reject at

Since p-value (0.0002) is less than the significance level (0.05), therefore, Null Hypothesis is rejected.

Therefore, based on the evidence the mean (average value of the dependent variable) is not the same for all groups.


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