For a normal population with a mean equal to 77 and a standard deviation equal to...

For a normal population with a mean equal to 77 and a standard deviation equal to 14, determine the probability of observing a sample mean of 85 or less from a sample of size 8.

P (x less than or equal to 85) =

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Expert Solution

Solution:

Given that,

mean = = 77

standard deviation = = 14

n = 8

So,

= 77

= ( / $\sqrt$ n) = (14 / $\sqrt$ 8 ) = 4.9497

P ( 85 )

= P ( - /) < (85 - 77 / 4.9497 )

= P ( z < 8 / 4.949)

= P ( z < 1. 62 )

Using z table

= 0.9474

Probability = 0.9474

milcah answered 1 month ago

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