For a normal population with a mean equal to 87 and a standard deviation equal to...

For a normal population with a mean equal to 87 and a standard deviation equal to 15, determine the probability of observing a sample mean of 94 or less from a sample of size 18?

Expert Solution

Answer:

Given,

sample size = n = 18

mean = 87

standard deviation = 15

Here we have to determine P(X <= 94)

P(X <= 94) = P((x-mu)/s <= (94 - 87) / 15)

= P(z <= 0.47)

= 0.6808225 [since from z table]

= 0.6808

Required probability = 0.6808

orchestra answered 2 years ago

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