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In: Physics

What is the smallest area of ice 29 cm thick that will support a 85 kg...

What is the smallest area of ice 29 cm thick that will support a 85 kg man? The ice is floating in freshwater.

Solutions

Expert Solution

Let be the volume of the ice

Density = Mass/Volume

Mass=Density*Volume

Weight = Mass*g

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So Weight of ice = Density of ice * Volume of ice* g

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Weight of man,

=================

The buoyant force on ice must balance weight of ice and weight of man

Buoyant force = Density of fluid * Volume of displaced fluid*g

Let's assume that ice is completely submerged but it supports the man. In that case volume of displaced fluid is the same as the volume of ice.

Cancel g

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Volume = Area*Thickness

ANSWER:

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genius_generous answered 1 year ago
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