In: Economics
Ans. Demand function, p = 1100 - 30q
and Cost function, C = 20q^2 + 100q + 1500
a) at q = 40, from the demand fuction,
p = 1100 - 30*40
=> p = -100
As negative price level is not possible, so, it is not economically reasonable to have q = 40 units.
b) Total Revenue, TR = p*q = 1100q - 30q^2
The profit function, G = TR - C
=> G = 1100q - 30q^2 - (20q^2 +100q + 1500)
=> G = 1000q - 50q^2 -1500
c) To find the optmal quantity of output which maximises profit, differentiate the profit function with respect to q and equate the result with 0
=> dG/dq = 1000 - 100q = 0
=> q = 10 units
To check whether this is maximum or not, differentiate the profit function again with respect to q and substitute the above determined value of q,
d^2G/dq^2 = -100 < 0
As second order derivative is negative, so, at q = 10 units level of output, the firm is maximizing its profit. Thus, optimal level of production is q* = 10 units
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