In: Economics
Suppose a community faces a pollution problem because of
emissions from a polluter with MAC=36- 2E. The information on
pollution damages is given by MD=E .
(a) If there is a tax rate on emissions of $ 9/unit, then what is
the emission level choosen by the polluter in equilibrium? What is
the amount of its compliance costs?
(b) What is the socially efficient tax rate in the given
situation?
(c) Now imagine a situation where the polluter bargains with the
community ( let's say, with the community government) and offers to
pay $6 for each unit of emission ( i.e. $6/unit) it is allowed to
produce. What level of emissions is the community likely to allow?
What is the likely net gain to the community from allowing those
units of emissions?
(a) When there is a tax rate on emissions of $ 9/unit, the modified marginal abatement cost is
MAC = 36 - 2E - 9 = 25 - 2E
as for every unit of emission you reduce, you gain $9 in saved taxes and hence, is subtracted from the abatement cost.
Firm minimizes total abatement cost with respect to E.
This occurs at MAC = 0
i.e. E = 12.5 units.
When there is a tax rate on emissions of $ 9/unit, emission level choosen by the polluter in equilibrium is 12.5 units.
Compliance cost is given by amount paid in tax = 12.5*9 = 112.5
(b) Socially efficient emission level is given by MD=MAC
E=36 - 2E
E = 36/3 = 12
Socially efficient emission level is 12 units
Let the tax rate required to acheive this be t
MAC = 36 - 2E - t
Firm minimizes total abatement cost with respect to E.
This occurs at MAC = 0
36 - 2E - t = 0
Desired emission level is E = 12
For this, tax rate t must be such that 36 - 2*12 = t
i.e. t = $12
Therefore, socially efficient tax rate is $12/unit.
(c) If the polluter pays $6 to the community for every unit of pollution, MD is modified to be E - 6. Community minimizes TD which is at MD = 0 i.e. E = 6. Therefore, community allows 6 units of emission when paid $6/unit of emission.
Gain in payment from firm = 6E = 6*6 = 36
Loss due to emissions = E2 = 6*6
Net gain = 36 - 36 = 0