Consider the titration of 100.0 mL of 0.130 M
H2NNH2 (Kb= 3.0 x 10-6)
by 0.260...
Consider the titration of 100.0 mL of 0.130 M
H2NNH2 (Kb= 3.0 x 10-6)
by 0.260 M HNO3. Calculate the pH of the
resulting solution after the following volumes of have
been added: 0.0 mL, 20.0 mL, 40 mL, 50 mL, 100 mL.
Consider the titration of 100.0 mL of 0.100 M H2NNH2
(Kb=3.0E-6) by 0.200 M HNO3. Calculate the pH of the resulting
solution after the following volumes of HNO3 have been added.
A) 0.0 mL
B) 20.0 mL
C) 25.0 mL
D) 40.0 mL
E) 50.0 mL
F) 100.0 mL
Consider the titration of 100.0 mL of 0.400 M C5H5N by 0.200 M
HCl. (Kb for C5H5N = 1.7×10-9)
Part 1 Calculate the pH after 0.0 mL of HCl added.
pH =
Part 2 Calculate the pH after 35.0 mL of HCl added.
pH =
Part 3 Calculate the pH after 75.0 mL of HCl added.
pH =
Part 4 Calculate the pH at the equivalence point.
pH =
Part 5 Calculate the pH after 300.0 mL of HCl added....
Consider the titration of 100.0 mL of 0.400 M
C5H5N by 0.200 M HCl.
(Kb for C5H5N =
1.7×10-9)
Part 1
Calculate the pH after 0.0 mL of HCl added.
pH =
Part 2
Calculate the pH after 25.0 mL of HCl added.
pH =
Part 3
Calculate the pH after 75.0 mL of HCl added.
pH =
Part 4
Calculate the pH at the equivalence point.
pH =
Part 5
Calculate the pH after 300.0 mL of HCl added....
Consider the titration of 100.0 mL of 0.400 M
HONH2 by 0.200 M HCl.
(Kb for HONH2 = 1.1×10-8)
Part 1
Calculate the pH after 0.0 mL of HCl added.
pH =
Part 2
Calculate the pH after 40.0 mL of HCl added.
pH =
Part 3
Calculate the pH after 75.0 mL of HCl added.
pH =
Part 4
Calculate the pH at the equivalence point.
pH =
Part 5
Calculate the pH after 300.0 mL of HCl added....
Consider the titration of 100.0 mL of 1.00 M HA (Ka=1.0*10^-6)
with 2.00 M NaOH.
A. Determine the pH before the titration begins
B. Determine the volume of 2.00 M NaOH required to reach the
equivalence point
C. Determine the pH after a total of 25.0 mL of 2.00 M NaOH has
been added
D. Determine the pH at the equivalence point of the
titration.
Thank you in advance!
Consider the titration of 60.0 mL of 0.100 M NH3 Kb= 1.8 x 10^-5
with 0.150 M HCl. Calculate the pH after the following volumes of
titrant have been added: 40.5 mL & 60.0 mL
Consider the titration of 39.2 mL of 0.260 M HF with 0.215 M
NaOH. Calculate the pH at each of the following points.
A. Calculate the pH after the addition of 9.80 mL of base
B.Calculate the pH at halfway to the equivalence point.
C. Calculate the pH at the equivalence point.
Calculate the pH at each point listed for the titration of 100.0 mL of 0.100 M cocaine (Section 8 4, Kb = 2.6 × 10-6) with 0.200 M HNO3. The points to calculate are Va = 0.0, 10.0, 20.0, 25.0, 30.0, 40.0, 49.0, 49.9, 50.0, 50.1, 51.0, and 60.0 mL. Draw a graph of pH versus Va.
Consider the titration of a 22.0 −mL sample of 0.105 M HC2H3O2
with 0.130 M NaOH. Determine each of the following.
Part E
the pH at the equivalence point Express your answer using two
decimal places.
Part F
the pH after adding 6.00 mL of base beyond the equivalence point
Express your answer using two decimal places.
Consider the titration of a 20.0 −mL sample of 0.100 M HC2H3O2
with 0.130 M NaOH. Determine each of the following. a. the volume
of added base required to reach the equivalence point b.the pH
after adding 6.00 mL of base beyond the equivalence point Express
your answer using two decimal places.