Question

In: Statistics and Probability

An automotive researcher wanted to estimate the difference in distance required to come to a complete...

An automotive researcher wanted to estimate the difference in distance required to come to a complete stop while traveling 40 miles per hour on wet versus dry pavement. Because car type plays a role, the researcher used eight different cars with the same driver and tires. The breaking distance (in feet) on both wet and dry pavement is shown in the data below. Car 1 2 3 4 5 6 7 8 Wet 107 101 109 112 105 106 111 108 Dry 72 69 74 73 76 75 78 81 a) Construct a 99% Confidence Interval for the mean difference in stopping distance between wet and dry roads. b) Test whether there is a difference in stopping distances between wet and dry roads at 1% level of significance.

Solutions

Expert Solution

(a)

From the given data, values of difference = d = Wet - Dry is got as follows:

Car 1 2 3 4 5 6 7 8
Wet 107 101 109 112 105 106 111 108
Dry 72 69 74 73 76 75 78 81
d = Wet - Dry 35 32 35 39 29 31 33 27

From the d values, the following statistics are calculated:

n = 8

= 32.625

sd = 3.7773

SE = sd/

= 3.7773/ = 1.3355

= 0.01

ndf =n - 1 = 8 - 1 = 7

From Table, critical values of t = 3.4995

Confidence interval:

32.625 (3.4995 X 1.3355)

= 32.625 4.6735

= ( 27.9515 ,37.2985)

Confidence interval:

27.9515 < < 37.2985

(b)

Test statistic is given by:

t = 32.625/1.3355 = 24.4291

Since the calculated value of t = 24.4291 is greater than critical value of t = 3.4995, the difference is significant. Reject null hypothesis.

Conclusion:

The data support the claim that there is significant difference in stopping distances between wet and dry roads.


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