Question

In: Statistics and Probability

An automotive researcher wanted to estimate the difference in distance required to come to a complete...

An automotive researcher wanted to estimate the difference in distance required to come to a complete stop while traveling 40 miles per hour on wet versus dry pavement. Because car type plays a role, the researcher used eight different cars with the same driver and tires. The breaking distance (in feet) on both wet and dry pavement is shown in the data below. Car 1 2 3 4 5 6 7 8 Wet 107 101 109 112 105 106 111 108 Dry 72 69 74 73 76 75 78 81 a) Construct a 99% Confidence Interval for the mean difference in stopping distance between wet and dry roads. b) Test whether there is a difference in stopping distances between wet and dry roads at 1% level of significance.

Solutions

Expert Solution

(a)

From the given data, values of difference = d = Wet - Dry is got as follows:

Car 1 2 3 4 5 6 7 8
Wet 107 101 109 112 105 106 111 108
Dry 72 69 74 73 76 75 78 81
d = Wet - Dry 35 32 35 39 29 31 33 27

From the d values, the following statistics are calculated:

n = 8

= 32.625

sd = 3.7773

SE = sd/

= 3.7773/ = 1.3355

= 0.01

ndf =n - 1 = 8 - 1 = 7

From Table, critical values of t = 3.4995

Confidence interval:

32.625 (3.4995 X 1.3355)

= 32.625 4.6735

= ( 27.9515 ,37.2985)

Confidence interval:

27.9515 < < 37.2985

(b)

Test statistic is given by:

t = 32.625/1.3355 = 24.4291

Since the calculated value of t = 24.4291 is greater than critical value of t = 3.4995, the difference is significant. Reject null hypothesis.

Conclusion:

The data support the claim that there is significant difference in stopping distances between wet and dry roads.


Related Solutions

A researcher wanted to know if there is an age difference in the amount of time...
A researcher wanted to know if there is an age difference in the amount of time spent on social media. They collected data from 8 teenagers (13-18 years old) and 8 young adults (21-26 years old); they measured the average number of hours spent using all social media platforms over the course of a day. The mean hours spent on social media for teenage participants was 2.9750 with a variance of 1.0630 and the mean hours spent on social media...
According to an estimate, the mean income of attorneys was $66,271 in 2015. A researcher wanted...
According to an estimate, the mean income of attorneys was $66,271 in 2015. A researcher wanted to check if the current mean income of attorneys is greater than $66, 271. A random sample of 64 attorneys taken by this researcher produced a mean income of $69,484 with a standard deviation of $11,500. Test at the 5 % significant level whether the current mean income of all attorneys is greater than $66,271. Explain your conclusion in words.
A researcher wanted to know if there was a difference in the effectiveness training results between...
A researcher wanted to know if there was a difference in the effectiveness training results between permanent employees at a business and temporary employees at the same business. The two training methods were in-person training or via videos. After the training, each employee took a test to determine the effectiveness of the training. Draw the correct design for this experiment. (Hint: In the design, it is easier to start off with the training methodology.) Remember to clearly indicate what is...
The time required for an automotive center to complete an oil change service on an automobile...
The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal? distribution, with a mean of 15 minutes and a standard deviation of 4 minutes. ?(a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take? longer, the customer will receive the service for? half-price. What percent of customers receive the service for? half-price? ?(b) If the automotive center does not want...
The time required for an automotive center to complete an oil change service on an automobile...
The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal​ distribution, with a mean of 19 minutes and a standard deviation of 3 minutes. ​(a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take​ longer, the customer will receive the service for​ half-price. What percent of customers receive the service for​ half-price? ​(b) If the automotive center does not want...
The time required for an automotive center to complete an oil change service on an automobile...
The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal​ distribution, with a mean of 17 minutes and a standard deviation of 2.5 minutes. ​(a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take​ longer, the customer will receive the service for​ half-price. What percent of customers receive the service for​ half-price? ​(b) If the automotive center does not want...
A researcher wanted to see whether there was a difference between dogs, cats and ferrets in...
A researcher wanted to see whether there was a difference between dogs, cats and ferrets in the mean number of trials required to train them to touch a target with their nose. The researcher samples 6 dogs, 6 cats and 6 ferrets and trained them to touch a target with their nose. The amount of trials required for each animal is listed in the table below. The overall mean was MTotal = 23.5. Assume that the amount of trials distributes...
1. A researcher wanted to estimate the mean contributions made to charitable causes by all major...
1. A researcher wanted to estimate the mean contributions made to charitable causes by all major companies. A random sample of 18 companies produced by the following data on contributions (in millions of dollars) made by them. 1.8, 0.6, 1.2, 0.3, 2.6, 1.9, 3.4, 2.6, 0.2 2.4, 1.4, 2.5, 3.1, 0.9, 1.2, 2.0, 0.8, 1.1 Assume that the contributions made to charitable causes by all major companies have a normal distribution. a. What is the point estimate for the population...
QUESTION 16 A researcher wanted to see whether there was a difference between NYC citizens and...
QUESTION 16 A researcher wanted to see whether there was a difference between NYC citizens and Boston citizens in the amount of time (in hours) they spent outside during April 2020. He collected two samples – one of NYC citizens and the other of Boston citizens, and measured the amount of time each subject spent outside during April 2020. Sample #1 (of NYC citizens) contained 20 subjects (n1=24), the mean number of hours spent outside was M1=40, and the sample’s...
A researcher wanted to see whether there was a difference between NYC citizens and Boston citizens...
A researcher wanted to see whether there was a difference between NYC citizens and Boston citizens in the amount of time (in hours) they spent outside during April 2020. He collected two samples – one of NYC citizens and the other of Boston citizens, and measured the amount of time each subject spent outside during April 2020. Sample #1 (of NYC citizens) contained 24 subjects (n1=24), the mean number of hours spent outside was M1=40, and the sample’s variance was...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT