Question

Write a small C++ program with 4 functions (and main():

• getNumbers()- what is the return, what are the parameters?
• findMax()- what is the return, what are the parameters?
• findMin()-what is the return, what are the parameters?
• find()- should return the index of the element or a -1 indicating not found

The main function will call those methods and print the results of each.

1 // declare necessary variables
2 // declare array
3 double numbers[SIZE];
4 // Function prototypes
5
6 int main() {
7 // call getNumbers()with appropriate parameters passed
8    // print results of getNumbers()
9    // call and print results of findMax()
10    // call and print results of findMin()
11    // call and print results of find() when element is found
12    // call and print results of find() when element is not found
13 return 0;
14 }

1. NOTE: output should be user friendly, eg, for find(), the code should not print a cryptic 3 or -1, the message should explain the results.
2. No magic numbers.
3. Use const array parameter where appropriate.

.

Answer 1

program in c++

#include <iostream>

using namespace std;
void getNumbers(int size);
void findMax(const double arr[], int size);
void findMin(const double arr[], int size);
void find(const double arr[], double num, int size);
const int SIZE = 100;
int i,size;
double numbers[SIZE]; //making a double type array with size 100
void getNumbers(int size) //fn to input numbers into the array
{
cout<<"Enter the numbers :";
for(i=0;i<size;i++)
cin>>numbers[i];
}
void findMax(const double arr[], int size) //fn to find largest number in the array
{
double max=arr[0]; //initially considering first number as the largest
for(i=0;i<size;i++)
{
if(arr[i]>=max) /* if the traversed number greater than max then max is stored with the current number */
max=arr[i];
}
cout<<"The largest number in the array is "<<max;
}
void findMin(const double arr[], int size) //fn to find smallest number in the array
{
double min=arr[0]; //initially considering first number as the smallest
for(i=0;i<size;i++)
{
if(arr[i]<=min) /* if the traversed number less than min then min is stored with the current number */
min=arr[i];
}
cout<<"\nThe smallest number in the array is "<<min;
}
void find(const double arr[], double num, int size) /* fn to find the position of the number .position starts from 1 to n
as the user enter the input array */
{
int position,flag=0; //position varible to store position of element if found
for(i=0;i<size;i++)
{
if(arr[i]==num)
{
position=i; /* if found then that array index is stored in position and change the flag value to 1 */
flag=1;
break;
}
}
if(flag==1)
cout<<"\nThe number " <<num<<" found at position "<<position+1;
else
cout<<"\n The number "<<num<<" not found in the array"; /* else condition here represents flag=0,that is number not found in array */
}
  

int main()
{   
double num;
cout<<"Enter the size of the array:";
cin>>size;
getNumbers(size);
findMax(numbers,size);
findMin(numbers,size);
cout<<"\nEnter the number to be checked:";
cin>>num;
find(numbers,num,size);
return 0;
}

output

Enter the size of the array:5

Enter the numbers :2.3 1 0.5 6 4

The largest number in the array is 6

The smallest number in the array is 0.5

Enter the number to be checked:1

The number 1 found at position 2

Enter the size of the array:5

Enter the numbers :2.3 1 0.5 6 4

The largest number in the array is 6

The smallest number in the array is 0.5

Enter the number to be checked:8

The number 8 not found in the array

nb

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