Question

a store manager wishes to see if the number of absences of her employees is the same for each weekdayselecteda tandom week and abscencrs find the gollowing number os abscences

Answer 1

Test Statistics

E = Sum of all frequencies / Number of observations

E= 85/5 = 17

DF= n-1 = 5-1 = 4

DF = 4

P value at chi square = 8.2353 at df = 4

using excel function solver =CHISQ.DIST.RT(8.2353,4) we get

p value = 0.0833

Critical Value at 0.05 significance

From Chi Square table at 0.05 and df = 4 we get

Chi Square critical value = 9.4877

Pvalue = 0.0833 > alpha = 0.05 so fail to reject Ho

8.2353 < 9.4877 so fail to reject Null hypothesis

Hence There is no difference in the number of absence for each day of the week