Question

In: Physics

A long wire carrying a 4.5A current perpendicular to the xy-plane intersects the x-axis atx=?2.0cm. Part...

A long wire carrying a 4.5A current perpendicular to the xy-plane intersects the x-axis atx=?2.0cm.

Part A

At what point on the x-axis is the magnetic field zero if the two currents are in the same direction?

Express your answer using two significant figures.

x = cm

Part B

At what point on the x-axis is the magnetic field zero if the two currents are in opposite directions?

Express your answer using two significant figures.

x =   cm

Solutions

Expert Solution

you mentioned about two currents, but you only gave details for one of them. Two current values are required to solve the question so ill assume some value for I2 = 3.5 A and given I1 = 4.5 A

a) When the currents are flowing in the same direction, the 2 magnetic fields due to the 2 currents will be equal and opposite somewhere between the wires.
Since B = ?oI/(2?r),
B1 - B2 = 0
?o/(2?)[I1/(x - (-2)) - I2/(2 - x)] = 0
x = 2(I1 - I2)/(I1 + I2)
x = 2(4.5 - 3.5)/(4.5 + 3.5)
x = 0.25 cm

b) When the currents are in opposite directions, the magnetic fields due to each wire will be in opposite directions to the left of the 1st wire and to the right of the 2nd wire. The combined magnetic field to the left of the wires, however, will never be zero because the magnetic field contribution of the 1st wire, being the closest and having the higher current, will always be larger than that of the 2nd wire. So we only need to concern ourselves with some point to the right of the 2 wires:
B1 - B2 = 0
?o/(2?)[I1/(x + 2) - I2/(x - 2)] = 0
x = 2(I1 + I2)/(I1 - I2)
x = 2(4.5 + 3.5)/(4.5 - 3.5)
x = 16 cm


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