In: Chemistry
Use Examples 4.16 to determine the hybridization for each central atom ( respectively C, C, O, N)in the following molecule:
CH3COONH2
Group of answer choices
sp3, sp2, sp2, sp3
sp3, sp2, sp, sp2
sp3, sp2, sp , sp3d
sp3, sp2, sp3, sp3
Answer:-
Step 1:-
Hybridisation index (I) = GA + 1/2 (VE - V - C)
Where, GA = Number of groups or atoms attached to the central atom
VE = Number of valance electrons present in the central atom
V = Valance of the central atom
C = Charge (if species is ionic)
Step 2:-
After knowing the value of I, the hybrid state is predicted as:
Value of I | 2 | 3 | 4 | 5 | 6 | 7 |
Hybrid state of central atom | sp | sp2 | sp3 | sp3d | sp3d2 | sp3d3 |
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i) Taking *C atom as central atom:
I = 4 + 1/2 × (4 - 4 - 0) = 4 = sp3
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ii) Taking **C atom as central atom:
I = 3 + 1/2 × (4 - 4 - 0) = 3 = sp2
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iii) Taking *O atom as central atom:
I = 2 + 1/2 × (6 - 2) = 4 = sp3
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iv) Taking N atom as central atom:
I = 3 + 1/2 × (5 - 3) = 4 = sp3
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Hence , correct answer is option 4) - sp3 , sp2 , sp3 , and sp3 .