In: Chemistry
A 0.100 M solution of an enantiomercially pure chiral compound D has an observed rotation of +.26 degree in a 1-dm sample container. The molar mass of the compount is 143.0 g/mol.
a. What is the specific rotation of D? (deg mL/ g.dm)
b. What is the observed rotation if this solution is mixed with an equal volume of a solution that is .100 M in L, the enantiomer of D? (deg)
c. What is the observed rotation if the solution of D is diluted with an equal volume of solvent? (degree)
d. What is the specific rotation of D after the dilution described in part c? (deg mL/g.dm)
e. What is the specific rotation of L, the enantiomer of D, after the dilution described in part c? (deg mL/g.dm)
f. What is the observed rotation of 100mL of a solution that contains .01 mole of D and .005 mole of L? (Assume a 1-dm path length.) (degree)
a)
concentration = 0.100 x 143 = 14.3 g / L = 0.0143 g/mL
observed rotation = + 0.26 o
specific rotation = observed rotation / l x concnetration
= 0.26 / 1 x 0.0143
specific rotation = 18.2 deg .mL / g.dm
b)
equial volume and equal concnetrations of solutions mixed , racemic mixure formed.
observed rotation = 0 deg
c)
volume doubled , then concentration is halved.
c = 0.0143 / 2 = 0.00715
observed rotation = 18.2 x 0.00715 x 1
observed rotation = 0.13 deg
d)
specific rotation is uneffected by dilution
specific rotation = 18.2
e)
specific rotation of L = - 18.1
f)
moles= 0.01 - 0.005 = 0.005
concentration = 0.005 / 0.1 = 0.05 M
= 0.05 x 143 / 1000
= 0.00715
observed rotation = 0.00715 x 18.2 x 1
observed rotation = 0.13