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In: Statistics and Probability

Full-time college students report spending a mean of 32 hours per week on academic activities, both...

Full-time college students report spending a mean of 32 hours per week on academic activities, both inside and outside the classroom. Assume the standard deviation of time spent on academic activities is 6 hours.

If you select a random sample of 25 full-time college students, what is the probability that the mean time spent on academic activities is at least 30 hours per week?

Solutions

Expert Solution

Solution :

Given that ,

mean = = 32

standard deviation = = 6

n = 25

= 32 and

= / n = 6 / 25 = 1.2

P( 30) = 1 - P( 30)

= 1 - P(( - ) / (30 - 32) / 1.2)

= 1 - P(z -1.67)

= 1 - 0.0475

= 0.9525

Probability = 0.9525

orchestra answered 2 years ago
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