In: Chemistry
A. In the laboratory, a general chemistry student measured the
pH of a 0.538 M aqueous solution of
ethylamine,
C2H5NH2 to be
12.198.
Use the information she obtained to determine the Kb for
this base
B. She then measured the pH of a 0.538 M
aqueous solution of methylamine,
CH3NH2 to be
12.161.
Use the information she obtained to determine the Kb for
this base
(these are 2 parts of the same question, please answer both!! :-) thank you! )
A)
C2H5NH2 + H2O ------------> C2H5NH3+ + OH-
0.538 0 0
0.538 - x x x
pH = 12.198
pOH = 1.802
[OH-] = 0.01578 M
Kb = x^2 / 0.538 - x
= (0.01578)^2 / 0.538 - 0.01578
Kb = 4.77 x 10^-4
B)
CH3NH2 + H2O ------------> CH3NH3+ + OH-
0.538 0 0
0.538 - x x x
pH = 12.161
pOH = 1.839
[OH-] = 0.01449 M
Kb = x^2 / 0.538 - x
= (0.01449 )^2 / 0.538 - 0.01449
Kb = 4.01 x 10^-4