Question

In: Chemistry

A. In the laboratory, a general chemistry student measured the pH of a 0.538 M aqueous...

A. In the laboratory, a general chemistry student measured the pH of a 0.538 M aqueous solution of ethylamine, C2H5NH2 to be 12.198.  
Use the information she obtained to determine the Kb for this base

B. She then measured the pH of a 0.538 M aqueous solution of methylamine, CH3NH2 to be 12.161.  
Use the information she obtained to determine the Kb for this base

(these are 2 parts of the same question, please answer both!! :-) thank you! )

Solutions

Expert Solution

A)

C2H5NH2 + H2O ------------> C2H5NH3+ +   OH-

0.538                                               0                  0

0.538 - x                                         x                   x

pH = 12.198

pOH = 1.802

[OH-] = 0.01578 M

Kb = x^2 / 0.538 - x

      = (0.01578)^2 / 0.538 - 0.01578

Kb = 4.77 x 10^-4

B)

CH3NH2 + H2O ------------> CH3NH3+ +   OH-

0.538                                               0                  0

0.538 - x                                         x                   x

pH = 12.161

pOH = 1.839

[OH-] = 0.01449 M

Kb = x^2 / 0.538 - x

      = (0.01449 )^2 / 0.538 - 0.01449

Kb = 4.01 x 10^-4


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