We are testing the hypothesis of no difference between means of two normally distributed populations (eg...

We are testing the hypothesis of no difference between means of two normally distributed populations (eg number of cracks in bricks). Alternative hypothesis is inequality. Significance is .05. Samples from these populations are X {3,5,6,9] and Y [6,11,15,21]

Sample correlation coefficient p=.993 , V(x) = 6.25 and V(Y) = 40.25

What test is appropriate (explain)?

Calculate appropriate test statistic (two tailed) and the P-Value using table?

State Conclusion

Solutions

Expert Solution

What test is appropriate (explain)?

The most appropriate test is the t test for two independent samples for the difference of means. This is because the sample size is small and the parents distributions are normal.

Calculate appropriate test statistic (two tailed) and the P-Value using table?

the t-statistic is computed as follows:

The p-value is p = 0.0701

Since it is observed that ∣t∣=2.2≤tc=2.447, it is then concluded that the null hypothesis is not rejected.

It is concluded that the null hypothesis Ho is not rejected. Therefore, there is not enough evidence to claim that the population mean μ1 is different than μ2, at the 0.05 significance level.

Please let me know in comments if anything is unclear. Will reply ASAP. Please upvote if satisfied!

orchestra answered 1 year ago

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