Explain why it is necessary to include the density of and the value of the acceleration due to gravity

Explain why it is necessary to include the density of and the value of the acceleration due to gravity, g, in a precise definition of a millimeter of mercury (page 196).

Expert Solution

A millimeter of mercury is 1/760 of an atmosphere of pressure at sea level. The density of mercury (13.5951 g/cm³) needs to be included in this definition and, because the density of mercury, like that of other liquids, varies somewhat with temperature, the pressure will vary if the density varies. The acceleration due to gravity (9.80665 m/s²) needs to be included because pressure is a force per unit area, not just a mass per unit area, and this force depends on the acceleration applied to the given mass, i.e., force = mass × acceleration.

Millimeter of mercury: 1/760 atm at sea level. Density and gravity affect pressure due to mass and force.

Junaid answered 8 months ago

a.) Is the acceleration due to gravity a constant or will it vary from place to...

a.) Is the acceleration due to gravity a constant or will it vary from place to place on Earth? b.) What about on another planet or moon? c.) How does Newton's second law of motion compare to Universal Gravitation?

The surface pressure on Venus is 92.00 atmatm, and the acceleration due to gravity there is...

The surface pressure on Venus is 92.00 atmatm, and the acceleration due to gravity there is 0.894 gg. In a future exploratory mission, an upright cylindrical tank of benzene is sealed at the top but still pressurized at 92.00 atmatm just above the benzene. The tank has a diameter of 1.80 mm , and the benzene column is 11.10 mm tall. Ignore any effects due to the very high temperature on Venus. A) What total force is exerted on the...

Please write legibly. Thank you. 1. Is the acceleration due to gravity a universal constant? Explain....

Please write legibly. Thank you. 1. Is the acceleration due to gravity a universal constant? Explain. 2. Is the acceleration due to gravity of objects affected by the Earth’s rotation? Explain.

What is the acceleration due to gravity on (a) Venus, (b) Pluto, and (c) the moon?

a) What is the acceleration due to gravity on (i) Venus, (ii) Pluto, and (iii) the...

a) What is the acceleration due to gravity on (i) Venus, (ii) Pluto, and (iii) the moon? b) Three objects, carrying charges of –4.0 x 10–6 C, –6.0 x 10–6 C and +9.0 x 10–6 C, respectively, are placed in a line, equally spaced from left to right by a distance of 0.50 m. Calculate the magnitude and direction of the next force acting on each that results from the presence of the other two.

2.) For this problem the heights are low enough that the acceleration due to gravity can...

2.) For this problem the heights are low enough that the acceleration due to gravity can be approximated as -g. (Note: even at low Earth orbit, such as the location of the International Space Station, the acceleration due to gravity is not much smaller then g. The apparent weightlessness is due to the space station and its occupants being in free-fall.) A rocket is launched vertically from a launchpad on the surface of the Earth. The net acceleration (provided by...

2: For this problem the heights are low enough that the acceleration due to gravity can...

2: For this problem the heights are low enough that the acceleration due to gravity can be approximated as -g. (Note: even at low Earth orbit, such as the location of the International Space Station, the acceleration due to gravity is not much smaller then g. The apparent weightlessness is due to the space station and its occupants being in free-fall.) A rocket is launched vertically from a launchpad on the surface of the Earth. The net acceleration (provided by...

On the moon the acceleration due to gravity is -1.6 m/s. a stone is dropped from...

On the moon the acceleration due to gravity is -1.6 m/s. a stone is dropped from a cliff on the moon and his the surface of the moon 40 seconds later. How do i find the position function of the stone?

On a planet, the acceleration due to gravity is only 7.2 m/s2. A person living on...

On a planet, the acceleration due to gravity is only 7.2 m/s2. A person living on that planet throws a football at 10 m/s at an angle of 48 degrees to the horizontal. The person is standing, so the ball launches from an initial height of 1.8 meters above the ground. (Ignore any air resistance here.) What maximum height from the ground would the ball reach? What would be the flight time before the ball gets back to the ground?

A rocket is fired from earth towards sun. Justify that acceleration due to gravity does not...

A rocket is fired from earth towards sun. Justify that acceleration due to gravity does not depend on mass of the rocket moving? Is the acceleration due to gravity on rocket at a point above earth, inversely related with square of distance of that point from earth? Explain shortly. Using the following data, how would you determine the point where the gravitational force on the rocket is zero? [ Note: neglect the attractive forces of other planets on the rocket]...

Question