Question

In the code cell below, use two input() commands to collect two positive, non-zero integers from the user. These values represent the starting and ending values of a range (you may assume that the first value is always strictly less than the second value).

Next, use a loop to examine and count every integer in the range (including the starting and ending values) that contains at least one 7 among its digits. When your loop ends, print the total number of integers that contain at least one 7 and no other output.

For example, the input values 42 and 75 would produce the result 9 (within that range, we have the numbers 47, 57, 67, 70, 71, 72, 73, 74, and 75).

for example:

# Assume that my_number already has a value

number_string = str(my_number)

if 7 in number_string: # Add the rest of your code below...

Answer 1

Python code:

#accepting starting value
start=int(input())
#accepting ending value
end=int(input())
#setting count of numbers having 7 as 0
count=0
#looping each number in range
for my_number in range(start,end+1):
    #converting that number to string
    number_string=str(my_number)
    #checking if 7 is in that string
    if '7' in number_string:
        #incrementing count
        count+=1
#printing count
print(count)

Screenshot:

Input and Output: