Find a general solution to the differential equation using the
method of variation of parameters.
y''+ 25y= sec5t
The general solution is y(t)= ___
y''+9y= csc^2(3t)
The general solution is y(t)= ___
Using variation of parameters, find a particular solution of the
given differential equations:
a.) 2y" + 3y' - 2y = 25e-2t (answer should be: y(t) =
2e-2t (2e5/2 t - 5t - 2)
b.) y" - 2y' + 2y = 6 (answer should be: y = 3 + (-3cos(t) +
3sin(t))et )
Please show work!
Using method of variation of parameters, solve the differential
equation: y''+y'=e^(2x)
Find the general solution, and particular solution using this
method.