In: Statistics and Probability
You measure 48 textbooks' weights, and find they have a mean
weight of 54 ounces. Assume the population standard deviation is
11.7 ounces. Based on this, construct a 90% confidence interval for
the true population mean textbook weight.
Give your answers as decimals, to two places
Solution :
Given that,
= 54
= 11.7
n = 48
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z0.05 = 1.645
Margin of error = E = Z/2* ( /n)
= 1.645 * (11.7 / 48)
=2.78
At 90% confidence interval estimate of the population mean is,
- E < < + E
54 - 2.78 < < 54 + 2.78
51.22< < 56.78
(51.22,56.78 )